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Korvikt [17]
3 years ago
12

Whole numbers with more digits are ____ than the whole numbers with fewer digits.

Mathematics
1 answer:
Kipish [7]3 years ago
3 0
Whole numbers with more digits are greater than whole numbers with fewer digits. 
 
Unless there is a decimal making the number have more digits then the answer to the blank would be greater than.
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In three hours, manufacturer z can make b ball bearings. manufacturer y can make b ball bearings in 4 hours. manufacturer x can
nekit [7.7K]
Each hour,
x makes b/6 bearings
y makes b/4 bearings
z makes b/3 bearings

Together, each hour, x, y and z together make
b/6+b/4+b/3=b(1/6+1/4+1/3)=b(2/12+3/12+4/12)=b(3/4)=3b/4 bearings.

Time to make b bearings =
b/(3b/4)=4/3 hours = 1 hour 20 minutes.

4 0
3 years ago
Pls help i will mark brainleist
lara [203]

Answer:

ok so term 9 coefficent 5 term factor 1 quotient division sign sum add sign product x signf

Step-by-step explanation:

6 0
3 years ago
Can anyone help me. Please
faust18 [17]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
Find all real zeros of number 11
tensa zangetsu [6.8K]
The answer is, x = 4,  \frac{3}{2}, -7

I'm about to basically type up a report on explaining this answer so bear with me :P

<em>Step 1.)</em> Factor 2x^{3}+  3x^{2}  +65x+84 using Polynomial Division.

Just a basic rundown of what polynomial division is. When using polynomial division for this problem we find all the factors of our constant, 84, and then see which one, when substituted for x, makes the expression equal zero. After we find our variable that makes the problem equal zero, we divide it into our original expression. Here's how it's done:

These are our factors of 84: 1, 2, 3, 4, 6, 7, 12, 14, 21, 28, 42, 84

strating from one and plugging in these numbers, the first one we come upon that works is 4. So, now we will divide. below is a picture of what it should look like.

After we divide, we get an answer of ( 2x^{2} +11x-21)(x-4)

<em>Step 2.)</em> split ( 2x^{2} +11x-21)(x-4) into two terms

To do that we multiply the coefficient of the first term (2) by the constant (-21)
So: 2*-21=-42

Now we ask "which two numbers add up to equal 11, but multiply to equal -42". Those two numbers are 14 and -3.

Now we basically split 11x as the sum of 14 and -3. So now our problem should look like this: (2x^{2}+14x-3x-21) (x-4)
<span><span>
</span></span><em>Step 3.)</em> Factor out the common terms in the first two terms, then the last two like this:

From this: (2x^{2}+14x-3x-21) (x-4)

To this: (2x(x+7)-3(x+7))(x-4)

<em>Step 4.)</em> Factor the term (x + 7) out of the parenthesis

After we do that, we are left with our problem looking like this:

(x+7)(2x-3)(x-4)

The last thing we do is set each parenthesis equal to zero and work it out to find our zeros.

(x+7) = 0
x = -7

(2x-3) =0
x =  \frac{3}{2}

(x-4)=0
x=4

That gives us our answer of our zeros being x = 4, \frac{3}{2}, -7

Thank you for our question! I hope this helped! Have an amazing day! :D

4 0
3 years ago
- 11/5 -2.4 1.6 15/10 - 2.25 in order from least to greatest
tatuchka [14]

Answer (least to greatest):

  1. -2.4
  2. -2.25
  3. -11/5
  4. 15/10
  5. 1.6

I hope this helps!

8 0
3 years ago
Read 2 more answers
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