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2 years ago

Find how many values of X does f(x)=5? Illustrate on the graph.

Mathematics

1 answer:

Fantom [35]2 years ago

3 0

Answer:

Step-by-step explanation:

The question is saying "How many x values are there when y = 5?"

The answer is 2.

When x ≈ 1 and when x = ≈ 2

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Eight less than seven times a number is six find the number

Leokris [45]

Answer:

Step-by-step explanation:

let the number be n , then

7n - 8 = 6 ( add 8 to both sides )

7n = 14 ( divide both sides by 7 )

n = 2

The number is 2

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2 years ago

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Step-by-step explanation:

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use Taylor's Theorem with integral remainder and the mean-value theorem for integrals to deduce Taylor's Theorem with lagrange r

Vadim26 [7]

Answer:

As consequence of the Taylor theorem with integral remainder we have that

$f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)}{2!}(x-a)^2 + \cdots + \frac{f^{(n)}(a)}{n!}(x-a)^n + \int^a_x f^{(n+1)}(t)\frac{(x-t)^n}{n!}dt$

If we ask that $f$ has continuous $(n+1)$ th derivative we can apply the mean value theorem for integrals. Then, there exists $c$ between $a$ and $x$ such that

$\int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}dt = \frac{f^{(n+1)}(c)}{n!} \int^a_x (x-t)^n d t = \frac{f^{(n+1)}(c)}{n!} \frac{(x-t)^{n+1}}{n+1}\Big|_a^x$

Hence,

$\int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}d t = \frac{f^{(n+1)}(c)}{n!} \frac{(x-t)^{(n+1)}}{n+1} = \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1} .$

Thus,

$\int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}d t = \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1}$

and the Taylor theorem with Lagrange remainder is

$f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)}{2!}(x-a)^2 + \cdots + \frac{f^{(n)}(a)}{n!}(x-a)^n + \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1}$ .

Step-by-step explanation:

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3 years ago

Which rule describes rotating 90° counterclockwise?

Serhud [2]

The first one answer

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2 years ago

Estimate the square root of 150 to the nearest tenth.

muminat

the answer is 12.2 for 150 rounded to nearest tenth

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