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Nata [24]
2 years ago
14

What is the conjugate and modulus of 2 – 6i?

Mathematics
2 answers:
Serjik [45]2 years ago
5 0

Answer:

2 + 6i

Step-by-step explanation:

It’s the same numbers with an opposite sign

docker41 [41]2 years ago
4 0

Answer:

Conjugate: 2 + 6i

Modulus: 0

Step-by-step explanation:

Conjugate: 2 + 6i

Modulus: 0

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The answer is -1.5. Hope this helps
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At a football game, 12 people are wearing red jerseys and 15 people are wearing white jerseys. Write the ratio of red to white j
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Answer:

12:15 (simplified: 4:5)

12/15 (simplified: 4/5)

12 to 15 (simplified: 4 to 5)

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A jar of natural peanut butter normally cost four dollars today it's on sale for $3.60 what is the percentage of the discount
kakasveta [241]
$4 is the original price of the jar consisting of peanut butter so therefor it = 100%. It's for sale at $3.60, so we divide $4 by 100% so we get the percentage for each cent and then we times it by 3.60 to get the percentage for $3.60 which is 90%. Now we subtract 90% from 100% to get the discounted percentage for 40cents :)

5 0
3 years ago
(I will mark brainliest) Will 3/8 + 2/8 be closer to 1/2 or 1? How do you know?
11111nata11111 [884]

Answer:

1/2

Step-by-step explanation:

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4 0
1 year ago
In the figure, triangle CAE is an enlargement of triangle CBD with scale factor of 4/3. The area of the smaller triangle is 9cm2
balandron [24]

Answer:

16 cm^2

Step-by-step explanation:

Given

\triangle CAE -- Bigger Triangle

\triangle CBD -- Smaller Triangle

k = \frac{4}{3} --- Scale factor

Area of CBD = 9

Required

Determine the area of CAE

The area of triangle CBD is:

A_1 = \frac{1}{2}bh

\frac{1}{2}bh = 9

The area of CAE is:

A_2 = \frac{1}{2}BH

Where:

B = \frac{4}{3}b and

H = \frac{4}{3}h

The above values is the dimension of the larger triangle (after dilation).

So, we have:

A_2 = \frac{1}{2}*\frac{4}{3}b * \frac{4}{3} * h

A_2 = \frac{1}{2}*\frac{4}{3} * \frac{4}{3} *b* h

A_2 = \frac{1}{2}*\frac{16}{9}  *b* h

Re-order

A_2 = \frac{16}{9}*\frac{1}{2}* b* h

A_2 = \frac{16}{9}*\frac{1}{2}bh

Recall that:

\frac{1}{2}bh = 9

A_2 = \frac{16}{9}*9

A_2 = 16

Hence, the area is 16 cm^2

3 0
3 years ago
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