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kolezko [41]
3 years ago
12

Find the 88 term of the arithmetic sequence 4,-1,-6

Mathematics
1 answer:
tresset_1 [31]3 years ago
8 0

Answer:

an = a1 + d(n - 1)

a88 = 4 + (-5)(88 - 1)

a88 = 4 + (-5)(87)

a88 = 4 - 435

a88 = -431

So, the 88th term of the arithmetic sequence is -431.

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6 / 1/3 = 18

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Ms. Smith bought a 6 pound bag of candy for her students. She gave away 3 pounds and ate 10 ounces of candy. How many ounces doe
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38oz

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6-3=3   3pounds-10ounces=38

3lb=48oz   48-10=38

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What are the solutions of x^2-12x+27
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6 0
3 years ago
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PLEASE HELP
arsen [322]

Answer:

Equation of line shown in the graph is : x= - 2

Step-by-step explanation:

Given,

a line passing through two points ( -2,2) and ( -2,-3).

We need to use two pint line equation:

y - y1 = (y2 - y1 / x2 - x1 ) (x - x1 )

Here , x1 = -2 ,x2 = -2 , y1 = 2 and y2 = -3

So we can plug corresponding values in the line equation.

We get:    y - 2 = {(-3 - 2) / ( -2 - (-2))} (x - (-2))

         y - 2 = (-5 /0 ) (x + 2)

      0 * (y - 2) = -5 (x+2)

          0 = -5x - 10

        10 = -5x

        x = -10/5 = -2

Hence x= -2 is the equation of line shown in the graph.

8 0
3 years ago
Fine the exact distance between the line 6x-y=-3 and the point (6,2). Show your work. Explain your answer.
AVprozaik [17]

Answer:

\sqrt{37} units

Step-by-step explanation:

If we draw a perpendicular from point (6,2) on the line 6x - y = - 3, then we have to find the length of the perpendicular.  

We know the formula of length of perpendicular from a point (x_{1}, y_{1} ) to the straight line ax + by + c = 0 is given by  

\frac{|ax_{1} + by_{1} +c |}{\sqrt{a^{2}+b^{2}}}

Therefore, in our case the perpendicular distance is  

\frac{|6(6)-2+3|}{\sqrt{6^{2} +(-1)^{2} } } = \frac{37}{\sqrt{37} } = \sqrt{37}  units. (Answer)

6 0
4 years ago
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