Find the limit of the function algebraically. x→−3 (x^2-9/x^3+3)
1 answer:
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Answer:
(a) 0.5333
(b) 0.6583
(c) 0.5583
(d) 0.7083
(e) 0.6167
Step-by-step explanation:
Denote the events as follows:
<em>A</em> = a competitor will advertise
<em>NA </em>= a competitor will not advertise
<em>L </em>= Low sales will be achieved
<em>M </em>= Medium sales will be achieved
<em>H </em>= High sales will be achieved
The data provided is of the form:
Low (L) Medium (M) High (H) Total
A 32 14 18 64
NA 21 12 23 56
Total 53 26 41 120
The probability of an event <em>E</em> is:
n (E) = favorable outcomes of event <em>E</em>
N = Total number of outcomes
(a)
Compute the probability that next week the competitor will advertise as follows:
Thus, the probability that next week the competitor will advertise is 0.5333.
(b)
Compute the probability that next week sales will not be high as follows:
Thus, the probability that next week sales will not be high is 0.6583.
(c)
The events of achieving a medium or high sales are mutually exclusive.
Since the sales achieved will either be medium or high. They cannot be both.
So, P (M ∩ H) = 0.
Compute the probability that next week there will be medium or high sales will be achieved as follows:
Thus, the probability that next week there will be medium or high sales will be achieved is 0.5583.
(d)
Compute the probability that next week either the competitor will advertise, or only low sales will be achieved as follows:
Thus, the the probability that next week either the competitor will advertise, or only low sales will be achieved is 0.7083.
(e)
Compute the probability that next week either the competitor will not advertise, or high sales will be achieved as follows:
Thus, the the probability that next week either the competitor will not advertise, or high sales will be achieved is 0.6167.