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Crank
3 years ago
6

A survey was done that asked students to indicate whether they enjoy reading or playing video games.

Mathematics
1 answer:
Xelga [282]3 years ago
5 0
8:1 because it's just and 8 to a 1
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7 1/8 - 3 2/3<br><br> faction plz
VashaNatasha [74]

Answer:

83/24

Step-by-step explanation:

Calculator.

8 0
3 years ago
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Helppppppppppppppppppppp i will put answers correct gets marked Brainlyest
ANEK [815]

Answer:

i am thinking it the last one

Step-by-step explanation:

7 0
3 years ago
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An advertisement for a popular weight-loss clinic suggests that participants in its new diet program lose, on average, more than
Sedbober [7]

Testing the hypothesis, it is found that:

a)

The null hypothesis is: H_0: \mu \leq 10

The alternative hypothesis is: H_1: \mu > 10

b)

The critical value is: t_c = 1.74

The decision rule is:

  • If t < 1.74, we <u>do not reject</u> the null hypothesis.
  • If t > 1.74, we <u>reject</u> the null hypothesis.

c)

Since t = 1.41 < 1.74, we <u>do not reject the null hypothesis</u>, that is, it cannot be concluded that the mean weight loss is of more than 10 pounds.

Item a:

At the null hypothesis, it is tested if the mean loss is of <u>at most 10 pounds</u>, that is:

H_0: \mu \leq 10

At the alternative hypothesis, it is tested if the mean loss is of <u>more than 10 pounds</u>, that is:

H_1: \mu > 10

Item b:

We are having a right-tailed test, as we are testing if the mean is more than a value, with a <u>significance level of 0.05</u> and 18 - 1 = <u>17 df.</u>

Hence, using a calculator for the t-distribution, the critical value is: t_c = 1.74.

Hence, the decision rule is:

  • If t < 1.74, we <u>do not reject</u> the null hypothesis.
  • If t > 1.74, we <u>reject</u> the null hypothesis.

Item c:

We have the <u>standard deviation for the sample</u>, hence the t-distribution is used. The test statistic is given by:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

The parameters are:

  • \overline{x} is the sample mean.
  • \mu is the value tested at the null hypothesis.
  • s is the standard deviation of the sample.
  • n is the sample size.

For this problem, we have that:

\overline{x} = 10.8, \mu = 10, s = 2.4, n = 18

Thus, the value of the test statistic is:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{10.8 - 10}{\frac{2.4}{\sqrt{18}}}

t = 1.41

Since t = 1.41 < 1.74, we <u>do not reject the null hypothesis</u>, that is, it cannot be concluded that the mean weight loss is of more than 10 pounds.

A similar problem is given at brainly.com/question/25147864

3 0
3 years ago
write the equation of a line that is parallel to y = - 3/2 x -1 and that passes through the point (4,6)​
maria [59]

Answer:

Step-by-step explanation:Given Equation of line has slope m=-3/2

So the line passing through (4,6) has the same slope because both are parallel

From slope intercept form we have

y-y1=m(x-x1)

y-6=-3/2(x-4)

y-6=-3/2x +3/2(4)

y=-3/2x+12

2y=-3x+24

3 0
3 years ago
What is the LCM of 15 and 25
Tresset [83]

Hello there!

Factors of 15: 1, 3, 5, 15

Factors of 25, 1, 5, 25

5*5*3=75

The least common factor of 15 and 25 is 75 is the right answer.

Hope this helps!

Thank you for posting your question at here on Brainly.

-Charlie

7 0
3 years ago
Read 2 more answers
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