Check all that apply. if cos0 = 13/5, then: ?

(2^8 ⋅ 3^−5 ⋅ 6^0)^−2 ⋅ 3 to the power of negative 2 over 2 to the power of 3, whole to the power of 4 ⋅ 2^28 (5 points)

Otrada [13]

Answer:

Step-by-step explanation:

(2^8 ⋅ 3^−5 ⋅ 6^0)^−2 ⋅ 3

(2^8 ⋅ 3^−5 ⋅ 6^0)^−6

(a^m)^n=a^m*n

So,

(2^8*-6) * (3^−5*-6) * (6^0*-6)

(2^-48) (3^30) (6^0)

a^0=1

So,

(2^-48) (3^30) (1)

(2^-48) (3^30)

I hope this helps you friend!

3 0

3 years ago

Help please solve <img src="https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B6x%5E5%2B11x%5E4-11x-6%7D%7B%282x%5E2-3x%2B1

Shkiper50 [21]

Answer:

$\displaystyle -\frac{1}{2} \leq x < 1$

Step-by-step explanation:

Inequalities

They relate one or more variables with comparison operators other than the equality.

We must find the set of values for x that make the expression stand

$\displaystyle \frac{6x^5+11x^4-11x-6}{(2x^2-3x+1)^2} \leq 0$

The roots of numerator can be found by trial and error. The only real roots are x=1 and x=-1/2.

The roots of the denominator are easy to find since it's a second-degree polynomial: x=1, x=1/2. Hence, the given expression can be factored as

$\displaystyle \frac{(x-1)(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)^2(x-\frac{1}{2})^2} \leq 0$

Simplifying by x-1 and taking x=1 out of the possible solutions:

$\displaystyle \frac{(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)(x-\frac{1}{2})^2} \leq 0$

We need to find the values of x that make the expression less or equal to 0, i.e. negative or zero. The expressions

$(6x^3+14x^2+10x+12)$

is always positive and doesn't affect the result. It can be neglected. The expression

$(x-\frac{1}{2})^2$

can be 0 or positive. We exclude the value x=1/2 from the solution and neglect the expression as being always positive. This leads to analyze the remaining expression

$\displaystyle \frac{(x+\frac{1}{2})}{(x-1)} \leq 0$

For the expression to be negative, both signs must be opposite, that is

$(x+\frac{1}{2})\geq 0, (x-1)$

Or

$(x+\frac{1}{2})\leq 0, (x-1)>0$

Note we have excluded x=1 from the solution.

The first inequality gives us the solution

$\displaystyle -\frac{1}{2} \leq x < 1$

The second inequality gives no solution because it's impossible to comply with both conditions.

Thus, the solution for the given inequality is

$\boxed{\displaystyle -\frac{1}{2} \leq x < 1 }$

7 0

2 years ago

The volume of the cuboid is 120 cm Find x 5 cm 4 cm

belka [17]

Answer:

6cm

Step-by-step explanation:

Volume of cuboid = length × breadth × height

Length = x

Breadth = 4cm

Height = 5cm

Volume = 120cm³

Volume = 4 × 5 × x

120 = 20x

Divide both sides by 20

20x/20 = 120/20

x = 6cm

I hope this was helpful, please mark as brainliest

7 0

3 years ago

you are planning a scavenger hunt for 20 campers. You plan to have 5 teams.one camper for each team will be recorder and the res

nikitadnepr [17]

Total number of campers = 20

Total number of teams = 5

⇒ Number of campers in each team = Total number of campers ÷ Total number of teams

⇒ Number of campers in each team = 20 ÷ 5

⇒ Number of campers in each team = 4

Number of recorders in each team = 1

⇒ Number of searchers in each team = Number of campers in each team - Number of recorders in each team

⇒ Number of searchers in each team = 4 - 1

⇒ Number of searchers in each team = 3

Hence, there will be 3 searchers in each team

7 0

3 years ago

Read 2 more answers

Simplify x 3 - 4 = 5

Zarrin [17]

Hello @Destroyerbossle,

How are you doing? In this case, assuming you mean:

$x^{3} -4=5$

the answer would be: x= $\sqrt[3]{9}$

I hope I helped! Contact me if you need further help!

Thank you,
Darian D.

5 0

3 years ago