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sweet-ann [11.9K]
4 years ago
10

The store employees held a frog leaping contest. Frog #1 jumped a distance of 8 feet 3 inches. Frog #2 jumped 2 yards 36 inches.

Which frog won the contest? By how much?​
Mathematics
1 answer:
Alexandra [31]4 years ago
8 0

Answer:

Frog 1 - 8 feet 3 inches =

8 feet x (1 yard/3 feet) = 2.667 Yards

3 inches x (1 foot /12 inches) x ( 1 yard / 3 feet) = 0.83 yards

So Frog 1 = 2.75 Yard

Frog 2 - 2 yards 36 inches

36 inches x (1 foot /12 inches) x (1 yard / 3 feet) = 1 Yard

So Frog 2 = 3 yards

Frog 2 won

It won by 3 - 2.75 = 0.25 Yards

0.25 yards x (3 feet / 1 yard) = 0.75 feet

0.75 feet x (12 inches /1 foot) = 9 inches

<u>So Frog 2 won by 9 inches</u>

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Answer:

  • In the first week, the number of type-1 cabinets produced was 15,
  • the number of type-2 cabinets produced was 30,
  • the number of type-3 cabinets produced was 65.

Step-by-step explanation:

If we let a, b, c represent the numbers of type-1, type-2, and type-3 cabinets produced in the first week, respectively, we can write three equations in these unknowns:

  • a + b + c = 110 . . . . . total cabinets for the first week
  • a + 2b - c = 10 . . . . relationship of quantities in the first week
  • 3a +0b +c = 110 . . . . total cabinets in the second week

It can be convenient to let a machine solver find the solution to this set of equations. Most graphing calculators can handle it, along with several web sites.

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Solving by hand, we can subtract the second equation from twice the first. This gives ...

  2(a +b +c) -(a +2b -c) - 2(110) -(10)

  a +3c = 210 . . . . simplify

Subtracting this from 3 times the third equation gives ...

  3(3a +c) -(a +3c) = 3(110) -(210)

  8a = 120 . . . . . simplify

  a = 15 . . . . . . . divide by 8

Using this in the third equation of the original set, we have ...

  3·15 +c = 110

  c = 65 . . . . . . subtract 45

Then, in the first equation, we get ...

  15 + b + 65 = 110

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The solution is (type-1, type-2, type-3) = (15, 30, 65) for the first week.

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