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sweet-ann [11.9K]
3 years ago
10

The store employees held a frog leaping contest. Frog #1 jumped a distance of 8 feet 3 inches. Frog #2 jumped 2 yards 36 inches.

Which frog won the contest? By how much?​
Mathematics
1 answer:
Alexandra [31]3 years ago
8 0

Answer:

Frog 1 - 8 feet 3 inches =

8 feet x (1 yard/3 feet) = 2.667 Yards

3 inches x (1 foot /12 inches) x ( 1 yard / 3 feet) = 0.83 yards

So Frog 1 = 2.75 Yard

Frog 2 - 2 yards 36 inches

36 inches x (1 foot /12 inches) x (1 yard / 3 feet) = 1 Yard

So Frog 2 = 3 yards

Frog 2 won

It won by 3 - 2.75 = 0.25 Yards

0.25 yards x (3 feet / 1 yard) = 0.75 feet

0.75 feet x (12 inches /1 foot) = 9 inches

<u>So Frog 2 won by 9 inches</u>

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Can someone solve this
marysya [2.9K]

From the Arithmetic Information given, Pr = 0.049375 ≠ -8.050625 ≠ 0.0325  See explanation below.

<h3>

What are the step by steps solution to the questions above?</h3>

First, lets us restate the question properly. We have

Pr = 1 - ((6*12+6)/80)² = 1 - ((9*12²)/1600) - ((3*12*6)/1600) - (6²/6400) = 1 - 0.005625 * 12² - 0.001875 * 12 * 6 - 0.00015625 * 6²

Note that there are three equals signs. So lets divide the problem according and solve for the different parts.

Lets   1 - ((6*12+6)/80)²  ............A

1 - ((9*12²)/1600) - ((3*12*6)/1600) - (6²/6400) .............B; and

1 - 0.005625 * 12² - 0.001875 * 12 * 6 - 0.00015625 * 6² ........C

Solving for A we have

1 - (78/80)²

= 1 - (0.975)²

= 1 - 0.950625

A = 0.049375


Solving for B we have

1 - ((9*12²)/1600) - ((3*12*6)/1600) - (6²/6400)

= 1- (14,256/1600) - (216/1600) - (36/6400)
= 1 - 8.91 - 0.135 - 0.005625

B = -8.050625

Solving for C we have

1 - 0.005625 * 12² - 0.001875 * 12 * 6 - 0.00015625 * 6²

= 1 - 0.005625 * 144 - 0.001875 * 12 * 6 - 0.00015625 * 144

= 0.0325


In summary we can state that:

A = 0.049375

B =  -8.050625

C = 0.0325

Given that there were no abstract quantities, we can state that

Pr = A ≠ B ≠C or

Pr = 0.049375 ≠ -8.050625 ≠ 0.0325

Learn more about equations with equal signs at

brainly.com/question/18924248
#SPJ1

4 0
2 years ago
Look at this set of 9 numbers:
Mumz [18]
The median would stay the same
4 0
3 years ago
Read 2 more answers
If the scale factor is
klemol [59]

If the scale factor is 1/5, then the area of the preimage is multiplied by <u>0</u><u>.</u><u>2</u> or <u>1</u><u>/</u><u>5</u> to calculate the area of the new image.

6 0
2 years ago
Evaluate b-(-1/8)+c where b=2 and c=-7/4​
tatiyna

Answer:

3/8

Step-by-step explanation:

Evaluate b - -1/8 + c where b = 2 and c = -7/4:

b - (-1)/8 + c = 2 - (-1)/8 - 7/4

Put 2 + 1/8 - 7/4 over the common denominator 8. 2 + 1/8 - 7/4 = (8×2)/8 + 1/8 + (2 (-7))/8:

(8×2)/8 + 1/8 - (7×2)/8

8×2 = 16:

16/8 + 1/8 - (7×2)/8

2 (-7) = -14:

16/8 + 1/8 + (-14)/8

16/8 + 1/8 - 14/8 = (16 + 1 - 14)/8:

(16 + 1 - 14)/8

16 + 1 = 17:

(17 - 14)/8

| 1 | 7

- | 1 | 4

| 0 | 3:

Answer:  3/8

8 0
3 years ago
Please please helpp i will mark brainliest!!! 100 points !! ill mark brainliest if its correct.
Paraphin [41]

Answers and Step-by-step explanations:

1. We need to plug in values of x into the functions f(x) and g(x):

f(2) = 2.5 * 2 - 10.5 = -5.5                         g(2) = 64 * (0.5^2) = 16

f(3) = 2.5 * 3 - 10.5 = -3                            g(3) = 64 * (0.5^3) = 8

f(4) = 2.5 * 4 - 10.5 = -0.5                         g(4) = 64 * (0.5^4) = 4

f(5) = 2.5 * 5 - 10.5 = 2                             g(5) = 64 * (0.5^5) = 2

f(6) = 2.5 * 6 - 10.5 = 4.5                          g(6) = 64 * (0.5^6) = 1

2.

(a) Notice that at 14 on the x-axis, the blue line is above 4. Meanwhile, at 14, the red line is less than 2. Obviously, we can see that if the printed ad revenue was less than 2 and the online ad revenue was greater than 4, that's more than a double, so the lead marketing executive is correct.

(b) The approximate year that the revenues were equal is the place where the lines intersect. It's approximately at Year 7.5.

3.

(a) The Western Beach is clearly decreasing; it is decreasing by 2 ft per year. Meanwhile, the Dunes Beach is clearly increasing; it's increasing by 5 ft per year. (I'm not sure what kinds of "patterns" you're looking for).

(b) Year 11 and 12; this is because here, Western is going from 78 to 76 ft and Dunes is going from 75 to 80, so they'll likely coincide sometime in that time interval.

(c) One thing you can do is to create equations (of the form y = mx + b) for each of the beaches and then set those linear equations equal to each other.

6 0
3 years ago
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