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sweet-ann [11.9K]
4 years ago
10

The store employees held a frog leaping contest. Frog #1 jumped a distance of 8 feet 3 inches. Frog #2 jumped 2 yards 36 inches.

Which frog won the contest? By how much?​
Mathematics
1 answer:
Alexandra [31]4 years ago
8 0

Answer:

Frog 1 - 8 feet 3 inches =

8 feet x (1 yard/3 feet) = 2.667 Yards

3 inches x (1 foot /12 inches) x ( 1 yard / 3 feet) = 0.83 yards

So Frog 1 = 2.75 Yard

Frog 2 - 2 yards 36 inches

36 inches x (1 foot /12 inches) x (1 yard / 3 feet) = 1 Yard

So Frog 2 = 3 yards

Frog 2 won

It won by 3 - 2.75 = 0.25 Yards

0.25 yards x (3 feet / 1 yard) = 0.75 feet

0.75 feet x (12 inches /1 foot) = 9 inches

<u>So Frog 2 won by 9 inches</u>

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mamaluj [8]

Answer:

x = 18

y = 54

Step-by-step explanation:

A straight line equals 180 degrees.

Since Lines CD and AB are straight, we can deduce that the angle 3x = 2x + angle AN.

Because there is a right angle, we can subtract 90 -72 = 18.

18 + 2x = 3x

18 = x

A straight line equals 180 degrees. Once we figure out that x = 18, we can figure out y by plugging in x and then subtracting your answer from 180 degrees.

I hope this was helpful to you! If it was, please consider rating, pressing thanks, and giving my answer 'Brainliest.' Have a great day!

7 0
3 years ago
A school is planning to construct two rectangular play areas in the playground. The length of play area A must be 1 foot longer
Anna11 [10]

Answer:

А.The system has two solutions, but only one is viable because the other results in a negative width.

Step-by-step explanation:

Given

Let:

L_A \to length of play area A

W_A \to width of play area A

L_B \to length of play area B

W_B \to width of play area B

x \to Area of A

y \to Area of B

From the question, we have the following:

L_A = 1 + 4W_A

W_B = 2 + W_A

L_B = 2 + 3W_B

x = y

The area of A is:

x = L_A * W_A

This gives:

x = (1 + 4W_A) * W_A

Open bracket

x = W_A + 4W_A^2

The area of B is:

y = L_B * W_B

y = (2 + 3W_B) * ( 2 + W_A)

Substitute: W_B = 2 + W_A

y = (2 + 3(2 + W_A)) * ( 2 + W_A)

Open brackets

y = (2 + 6 + 3W_A) * ( 2 + W_A)

y = (8 + 3W_A) * ( 2 + W_A)

Expand

y = 16 + 8W_A + 6W_A + 3W_A^2

y = 16 + 14W_A + 3W_A^2

We have that:

x = y

This gives:

W_A + 4W_A^2 = 16 + 14W_A + 3W_A^2

Collect like terms

4W_A^2 - 3W_A^2 + W_A  -14W_A  - 16 =0

W_A^2  -13W_A  - 16 =0

Using quadratic calculator, we have:

W_A = -14.1 or W = 1.13 --- approximated

But the width can not be negative; So:

W = 1.19

7 0
3 years ago
Alyssa took a math test with 20 questions and she answered 16 questions correctly. In order get an A, she needs to answer at lea
ElenaW [278]
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C. In order to figure this question out you have to think that with every incorrect answer that Jessie answered she got three correct along with the one incorrect. By going with that information it can be figured that Jessie's score is 15 correct answers and 5 incorrect information if you go by the ratio 3:1 then go up tell the sides equal up to a total of 20 after being added. So Jessie's score again was 15 out of 20.
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OleMash [197]

Answer:

the last option

Step-by-step explanation:

can you show the rest of the last option? if there isn't anything cutoff, then the last option would be correct. also, you can use desmos .com next time to help you graph

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solniwko [45]

Yo sup??

cosx>0 in the 1st and 4th quadrant.

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