<u>Answer:</u>
gradient = = 
y-intercept = 
<u>Step-by-step explanation:</u>
• The slope-intercept form of an equation takes the general form:
,
where:
m = slope,
c = y-intercept.
• We are given the equation:
To change this into the slope-intercept form, we must make y the subject:
[subtract 
from both sides]
⇒ 
[divide both sides by 3]
⇒
• Comparing this equation with the general form equation, we see that:
m =
c = .
This means that the gradient is 
, and the y-intercept is 
.
To solve this problem,lets say that
X = the weight of the machine components. <span>
<span>X is normally distributed with mean=8.5 and sd=0.09
We need to find x1 and x2 such that
P(X<x1)=0.03 and P(X>x2)=0.03
<span>Standardizing:
<span>P( Z< (x1 - 8.5)/0.09 ) =0.03
P(Z > (x2 - 8.5)/0.09 ) =0.03.
<span>From the Z standard table, we can see that approximately P
= 0.03 is achieved when Z equals to:</span></span></span></span></span>
<span>z = -1.88 and z= 1.88</span>
Therefore,
P(Z<-1.88)=0.03 and P(Z>1.88)=0.03 <span>
So,
(x1 - 8.5)/0.09 = -1.88 and
(x2 - 8.5)/0.09 =1.88
Solving for x1 and x2:
<span>x1=-1.88(0.09) + 8.5 and
<span>x2=1.88(0.09) + 8.5
<span>Which yields:
<span><span>x1 = 8.33 g</span>
<span>x2 = 8.67 g</span></span></span></span></span></span>
<span>Answer: The bottom 3 is separated by the weight
8.33 g and the top 3 by the weight 8.67 g.</span>
Answer:
Fraction: 7/9
decimal: 0.778
Step-by-step explanation:
Answer:
568 square ft.
Step-by-step explanation:
11x24=264
19x16=304
264+304=568
Answer: p < 24
Step-by-step explanation: I'm assuming you mean solving for P
1. We want to get p alone and the first step would be to subtract 4 from both side which will give us: ⅔p < 16
2. Next step would to be multiplying by 3 from both sides and doing this will cancel out the 3 in the denominator giving you: 2p < 48
3. Now we have to divide both sides by 2 and we are done which gives us:
<u>p < 24</u>
<u></u>
Don't forget if we were to be dividing by a negative the sign would flip
(for example: -2p < 6 = p > 3) this isn't used in this problem but just a reminder if you see this in future problems
