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Tanya [424]
3 years ago
9

Simplify quantity 4 x squared plus 12 x minus 16 all over quantity 2x plus 10 over quantity 6 x plus 24 over quantity x squared

plus 9x plus 20
Mathematics
2 answers:
Softa [21]3 years ago
6 0
The answer is: (x-1)(x+4)/3
hope this helped! (:
ladessa [460]3 years ago
5 0

\frac{4x^2+12x-16}{\frac{2x+10}{\frac{6x+24}{x^2+9x+20}}}

Here we have two fractions top and bottom

\frac{4x^2+12x-16}{2x+10} divide by \frac{6x+24}{x^2+9x+20}

We have division in between . we reverse the second fraction and multiply it with first fraction.

\frac{4x^2+12x-16}{2x+10} * \frac{x^2+9x+20}{6x+24}

Now we factor both numerator and denominator

4x^2+12x-16 = 4 (x+4)(x-1)

2x+10 = 2(x+5)

x^2+9x+20 = (x+5)(x+4)

6x+24 = 6(x+4)

Replace the factors,

\frac{4 (x+4)(x-1)}{2(x+5)} * \frac{(x+5)(x+4)}{6(x+4)}

We cancel out same factors at the top and bottom

So it becomes , \frac{(x-1)(x+4)}{3}


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