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ddd [48]
3 years ago
14

A population of caribou in a forest grows at a rate of 6% every year. If there are currently 258 caribou, which function represe

nts the number of caribou in the forest in t years?
Mathematics
1 answer:
Dimas [21]3 years ago
6 0

Answer:

P(t) = 258( 1 + 6%)^t

Step-by-step explanation:

Given that the  population of caribou in a forest grows at a rate of 6% every year. If there are currently 258 caribou, the function representing the number of caribou in the forest in t years will be

P(t) = 258( 1 + 6%)^t

Since it is increasing, it will be 1 + 6%

Where P(t) is the function representing the population after t years.

258 is the current or initial population.

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3 0
3 years ago
Al saves pennines. He agreed to give 6/13 of his pennines to Bev if she would give 6/13 of what she got from Al to Carl and if C
Anuta_ua [19.1K]

Answer:

24,167 pennies

Step-by-step explanation:

Let's see what happens if we say Al had 1000 pennies.

Bev would get 6/13 of 1000 which is  462 pennies. ((6/13)*1000)

Continuing like this Carl would get (6/13)*462 = 213

Dani would get 213(6/13)=98

Now, another way of writing this is 1000*(6/13)*(6/13)*(6/13).  hopefully that makes sense, if not let me know.

Anyway, what is another way of writing this?  If it isn't clear how else can you write 3*3*3*3?  Exponents is the answer.  3*3*3*3=3^4 and (6/13)*(6/13)*(6/13)= (6/13)^3, so you can write the whole equation as 1000(6/13)^3=98

Now, using the information given in the question we know how much is gotten by Dani as well as (6/13)^3, but we don't know how much we start with.  So instead of 1,000 like I showed lets use a variable x.

x*(6/13)^3 = 2376

Now you can use algebra to solve for x

x*(6/13)^3 = 2376 step one let's just figure out what (6/13)^3 is.

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You can double check too with 24167*(6/13)^3

5 0
3 years ago
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