All categories

3 years ago

Please help me with this

Mathematics

1 answer:

quester [9]3 years ago

8 0

Cos = adjacent over hypotenuse so it would be A 24/25. 24 is adjacent to the angle 16° and 25 is the hypotenuse of the triangle. Hope this helps

You might be interested in

In Circle M, points A, B, and C are located on the circle such that measure angle CBM equals to 34 degrees. What represents angl

Bess [88]

Answer:

Angle CAB=56 degrees

Step-by-step explanation:

See the attached image for the diagram.

In triangle BMC

|BM|=|MC| (Radii of a Circle)

Therefore, triangle BMC is an Isosceles Triangle; and

$\angle CBM=\angle BCM=34^\circ$

$\angle CBM+\angle BCM+\angle BMC=180^\circ$ (sum of \angle s$ in a triangle)\\34^\circ+34^\circ+\angle BMC=180^\circ\\\angle BMC=180^\circ-68^\circ=112^\circ$

Next,

$\angle BMC=2\angle CAB $(Angle at center is twice angle at circumference)\\112^\circ=2\angle CAB\\\angle CAB=112^\circ \div 2\\\angle CAB=56^\circ$

7 0

3 years ago

Sandy bought 3/4 yard of red ribbon and 2/3 yard of white ribbon to make some hair bows.Altogether,how many yards of ribbon did

Stolb23 [73]

Sandy bought 1 and 5/12 yards of ribbon

5 0

4 years ago

Read 2 more answers

Evaluate the expression a/b for a = 80 and b = 8.

tangare [24]

A / B

= 80 / 8

= 10

Therefore the answer is 10

7 0

3 years ago

Read 2 more answers

Solve this two column proof! (25 pts!)

ahrayia [7]

Answer:

1.) Given

2.)Given

3.)Angle bisector

4.)Perp. Segments

5.)substitution

6.)Reflexive

7.)ASA postulate

8.)CPCTC

9.)Def of isosceles triangle

Step-by-step explanation:

6 0

3 years ago

Calculate an estimate of a square root of 119 + 120i

uysha [10]

Answer:

Step-by-step explanation:

Given

z=119+120 i

Let $\sqrt{119+120 i}=p+iq$

Squaring both sides

$119+120 i=p^2-q^2+2ipq$

Comparing real and imaginary part

Re(LHS)=Re(RHS)

$119=p^2-q^2$ -----------1

comparing Im(LHS)=Im(RHS)

120=2pq

$q=\frac{60}{p}$

Substitute q in 1

$119=p^2-(\frac{60}{p})^2$

$p^4-119p^2-(68)^2=0$

Let $x=p^2$

$x^2-119x-4624=0$

$x=frac{119\pm \sqrt{119^2+4\times 4624}}{2}$

$x=\frac{119\pm 180.71}{2}$

we take only Positive value because $p^2=x$

x=149.85

$p^2=149.85$

thus $p=\pm 12.24$

$q=\mp 4.90$

thus $\sqrt{119+120 i}=\pm (12.24+i 4.90)$

6 0

4 years ago