Question

Please help me ASAP!!!!

Answer 1

ANSWER

$34 {units}^{2}$

EXPLANATION

The width of the rectangle is |AB|

A(-1,4) and B(3,3)

We use the distance formula,

$d = \sqrt{ {(x_2-x_1)}^{2} + {(y_2-y_1)}^{2} }$

This implies that,.

$d = \sqrt{ {(3- - 1)}^{2} + {(3 - 4)}^{2} }$

$d = \sqrt{ {(4)}^{2} + {( - 1)}^{2} }$

$d = \sqrt{ 16+ 1 }$

$d = \sqrt{17}$

The length is BC

C(1,-5) and B(3,3)

$d = \sqrt{ {(3- 1)}^{2} + {(3 - - 5)}^{2} }$

$d = \sqrt{ {2}^{2} + {(8)}^{2} }$

$d = \sqrt{4 + 64 }$

$d = \sqrt{68}$

$d = 2 \sqrt{17}$

The area is

$= l \times w$

$= 2 \sqrt{17} \times \sqrt{17}$

$2 \times 17 = 34 {units}^{2}$