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3 years ago

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Fred begins walking toward John house at 3 mi/h. John leaves his house at the same time and walks toward Fred's house on the sam

e path at a rate of 2 mi/h. How long will it be before they meet if the distance between the houses is 4 miles?

1 answer:

Tcecarenko [31]3 years ago

7 0

Let us assume as at when they meet, the time elapsed is x hours.

Fred 3 mi/h
John 2 mi/h

Distance = speed * time

Fred = 3x
John = 2x

Houses are 4miles apart.
So: 3x + 2x = 4 5x = 4

x = 4/5 hour = 0.8 hour or 0.8*60 = 48 minutes

Time elapsed is 0.8 hour or 48 minutes.

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4 years ago

Linda calculated that the saucer for her teacup has an area of 50.24 square centimeters. What is the saucer's circumference?

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Answer:

The saucer's circumference is <u>25.12 centimeter</u>.

Step-by-step explanation:

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Linda calculated that the saucer for her tea cup has an area of 50.24 square centimeters.

Use 3.14 for π.

Now, to find the saucer's circumference.

So, we get the radius first by putting the formula of area:

Area = 50.24 square centimeters.

Let radius be $r.$

$Area = \pi r^2.$

$Area = \pi\times r^2.$

As given we use 3.14 for π.

$50.24 = 3.14\times r^2.$

<em>Dividing both sides by 3.14 we get:</em>

$16=r^2.$

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Thus, the radius = 4 centimeters.

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$Circumference=2\pi r$

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Circumference = 25.12 centimeter.

Therefore, the saucer's circumference is 25.12 centimeter.

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4 years ago