WHOEVER ANSWERS FIRST GETS BRAINLIEST PLSSSSS HELP MEH
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Answer:
See below.
Step-by-step explanation:
The question doesn't ask you to find the area, it just ask for the expression that represents the area.
The area of rectangle is A=bh, where b and h are each of the side lengths.
Since we know the sides are (2x+7) and (5x+9), this means that the expression for the area of the rectangle is:
To find the degree and classification, expand the factors:
Thus, this is a second degree quadratic expression
And from Part A, when we multiplied (2x+7)(5x+9), we got another polynomial (10x^2+52x+63). Thus, this rerepresents the closure property of polynomials, where multiplying a polynomial by another gets another polynomial.
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The equation of the tangent to the curve at the point P(2, -10) is:
y = 8x - 26
We need to find the coordinates of point Q where the slope of the tangent to the curve f(x) must also be 8.
Now we have a quadratic:
which simplifies to:
which factorizes to:(x + 4)(x - 2) = 0
Therefore x = -4, 2.
f(-4) = 48
Therefore the coordinates of Q are (-4, 48).
y = 8x - 26
We need to find the coordinates of point Q where the slope of the tangent to the curve f(x) must also be 8.
Now we have a quadratic:
which simplifies to:
which factorizes to:(x + 4)(x - 2) = 0
Therefore x = -4, 2.
f(-4) = 48
Therefore the coordinates of Q are (-4, 48).