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irina [24]
3 years ago
15

Forty percent of the dogs in the image have been adopted. How many of the dogs have been adopted? (There are five dogs in this p

icture)
A) 1 dog
B) 2 dogs
C) 3 dogs
D) 4 dogs
Mathematics
2 answers:
Jlenok [28]3 years ago
5 0

Answer:

<em>B) </em><em>2 dogs.</em>


<h2><em>40% of 5 = 2</em></h2>
Juliette [100K]3 years ago
5 0

Answer:

b

Step-by-step explanation:

the answer is b because 5 dogs =100%

if you divide 100 by 5 you get 20

so that means,

5 dogs = 100%

4 dogs = 80%

3 dogs = 60%

2 dogs = 40%

1 dog = 20%

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Neko [114]

Answer:

1/3

Step-by-step explanation:

5 over 15

divide both by 5 to simplify 1 over 3

3 0
3 years ago
In ΔDEF, the measure of ∠F=90°, DE = 70 feet, and EF = 57 feet. Find the measure of ∠D to the nearest tenth of a degree.
kondor19780726 [428]

Answer:

  54.5°

Step-by-step explanation:

You know that in a right triangle, the sine of an angle is given by ...

  Sin = Opposite/Hypotenuse

  sin(D) = EF/ED = 57/70

The inverse sine function is used to find the angle:

  ∠D = arcsin(57/70)

  ∠D ≈ 54.5°

5 0
3 years ago
What is 4,726,000 rounded to the nearest million?
just olya [345]

Answer:

5,000,000

Step-by-step explanation:


6 0
3 years ago
AYUDA CON ESTO!!! ALGUIEN PORFAVOR
Gre4nikov [31]

Answer:

Problem 1)  frequency:  160 heartbeats per minute, period= 0.00625 minutes (or 0.375 seconds)

Problem 2) Runner B has the smallest period

Problem 3) The sound propagates faster via a solid than via air, then the sound of the train will arrive faster via the rails.

Step-by-step explanation:

The frequency of the football player is 160 heartbeats per minute.

The period is (using the equation you showed above):

Period = \frac{1}{frequency} = \frac{1}{160} \,minutes= 0.00625\,\,minutes = 0.375\,\,seconds

second problem:

Runner A does 200 loops in 60 minutes so his frequency is:

\frac{200}{60} = \frac{10}{3} \approx  3.33   loops per minute

then the period is: 0.3 minutes (does one loop in 0.3 minutes)

the other runner does 200 loops in 65 minutes, so his frequency is:

\frac{200}{65} = \frac{40}{13} \approx  3.08   loops per minute

then the period is:

\frac{13}{40} =0.325\,\,\,minutes

Therefore runner B has the smaller period

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3 years ago
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vfiekz [6]

Answer:

17.1

Step-by-step explanation:

If you have 15.50 and you divide 0.75 you get 20.6 and if you subtract 3.50 you get 17.1 which is your answer. Boom

7 0
2 years ago
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