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dmitriy555 [2]
3 years ago
6

Two numbers are in the ratio 2:3 and their sum id 45 then find both numbers​

Mathematics
2 answers:
Nimfa-mama [501]3 years ago
8 0

Now we have to,

find the both required numbers.

It is given that,

→ Two numbers are in the ratio 2:3.

→ Their sum is 45.

Now assume numbers as,

→ 2y and 3y

As per the given information,

→ 2y + 3y = 45

First we can find the value of y,

→ 2y + 3y = 45

→ 5y = 45

→ y = 45/5

→ [y = 9]

The given ratio is,

→ 2 : 3

Let's find the value of 2y,

→ 2y --- {y = 9}

→ 2 × (9)

→ 18

Let's find the value of 3y,

→ 3y --- {y = 9}

→ 3 × (9)

→ 27

Hence, the number is 18 and 27.

iragen [17]3 years ago
7 0

Let the numbers be 2x and 3x.

<u>According to the Question</u>,

⇒ 2x + 3x = 45

⇒ 5x = 45

⇒ x = 45/5

⇒ x = 9

<u>Now finding the values of both the number,</u>

⇒ 2x = 2 × 9

= 18

⇒ 3x = 3 × 9

= 27

<u>Hence, the value of both the number is 18 and 27 respectively.</u>

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Area of trapezium = 4.4132 R²

Step-by-step explanation:

Given, MNPK is a trapezoid

MN = PK and ∠NMK = 65°

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Now, sum of interior angles in a quadrilateral of 4 sides = 360°.

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consider triangle NOS;

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Now, draw a line parallel to ST from N to line MK

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⇒ MT = 1.5696 R

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Now, area of trapezium is (sum of parallel sides/ 2)×(distance between them).

⇒ A = (\frac{NP + MK}{2}) × (ST)

       = (\frac{1.274 R + 3.1392 R}{2}) × 2 R

       = 4.4132 R²

⇒ Area of trapezium = 4.4132 R²

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