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Sindrei [870]
3 years ago
9

Can someone please help me?!?!?

Mathematics
1 answer:
Anna11 [10]3 years ago
6 0
They are equal. They're equal because if you simplify 500/600, it becomes 5/6.
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Please answer this correctly without making mistakes I want ace expert and genius people to answer this correctly without making
77julia77 [94]

Answer:

24

Step-by-step explanation:

im an expert but I did this on my calculator

hope this helped tho

6 0
3 years ago
15 POINTS FOR ANSWER: Complete the table with equivalent ratios. Then, write them as ordered pairs. (Write them in the text box
scZoUnD [109]

Answer:

Top row: 3,6,9,12,15

Bottom row: 5,10,15,20,25

Step-by-step explanation:

As ordered pairs/ratio form:

3:5, 6:10, 9:15, 12:20, 15:25

6 0
3 years ago
Read 2 more answers
The graph shows the data points in the table and the exponential regression model associated with the data ?
Ipatiy [6.2K]
From the graph, it is obvious that the trend is decreasing from 100 on day 2, to 1 on day 10. So, the answer could either be A or C. The question would be how fast is it decreasing? To illustrate this, let's find the difference of consecutive data:

100 - 26 = 74
26 - 6 = 20
6 - 2=4
2-1=1

It must not be an additive rate because there is no common difference. Let's illustrate if the trend is in multiplicative rate:

100/26 = 3.85
26/6 = 4.33
6/2 = 3
2/1 = 2

More or less, they have a common divider. Hence, the decreasing rate is in multiplicative rate. The answer is A.
6 0
3 years ago
Read 2 more answers
Wynona buys some new boots that are priced $85.79. She gets successive discounts of 10% followed by 5% off on the boots. The pur
kotegsom [21]

Answer:84.5%

Step-by-step explanation:Subtract  85.79 from 10.5 that will give you 84.5.

3 0
3 years ago
What degree of rotation is represented on this matrix
Korvikt [17]

Answer:

Option B is correct

the degree of rotation is, -90^{\circ}

Step-by-step explanation:

A rotation matrix is a matrix that is used to perform a rotation in Euclidean space.

To find the degree of rotation using a standard rotation matrix i.e,

R = \begin{bmatrix}\cos \theta & -\sin \theta \\ \sin \theta & \cos \theta \end{bmatrix}

Given the matrix: \begin{bmatrix}0 & 1 \\ -1 & 0\end{bmatrix}

Now, equate the given matrix with standard matrix we have;

\begin{bmatrix}\cos \theta & -\sin \theta \\ \sin \theta & \cos \theta \end{bmatrix} =  \begin{bmatrix}0 & 1 \\ -1 & 0\end{bmatrix}

On comparing we get;

\cos \theta = 0       and -\sin \theta =1  

As,we know:

  • \cos \theta = \cos(-\theta)
  • \sin(-\theta) = -\sin \theta

\cos \theta = \cos(90^{\circ}) = \cos( -90^{\circ})

we get;

\theta = -90^{\circ}

and

\sin \theta =- \sin (90^{\circ}) = \sin ( -90^{\circ})

we get;

\theta = -90^{\circ}

Therefore, the degree of rotation is, -90^{\circ}

7 0
3 years ago
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