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shusha [124]
3 years ago
12

There are 8 people on the debate team. In how many ways can the coach choose 4 members to send to competition?

Mathematics
2 answers:
seropon [69]3 years ago
8 0

Answer:

70

Step-by-step explanation:

Given : There are 8 people on the debate team.

To Find: In how many ways can the coach choose 4 members to send to competition?

Solution:

We will use combination over here

Formula : ^nC_r=\frac{n!}{r!(n-r)!}

Now There are 8 people on the debate team and the coach have to choose 4

So, n = 8

r = 4

So, number of ways of choosing 4 people out of 8 = ^8C_4

                                                                                    = \frac{8!}{4!(8-4)!}  

                                                                                    = \frac{8!}{4!4!}  

                                                                                    = 70  

Hence there are 70 ways of choosing 4 members out of 8 to send to competition

meriva3 years ago
4 0

he can either send one half or the other half.

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Answer:

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Step-by-step explanation:

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To see that the given statement is false, consider a=1, b=3. The arithmetic mean is equal to (1+3)/2=2, and the geometric mean is equal to \sqrt{1\cdot 3}=\sqrt{3} but 2>\sqrt{3}, contrary to the statement (arithmetic>geometric in this case).

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Xander spends most of his time with his 10 closest friends. he has known 4 of his 10 friends since kindergarten. if he is going
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Probability that the first 2 of the friends to show up to the movie are friends he has known since kindergarten but the third not is 1/10

Total friends = 10

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P(E) = Favourable outcomes / Total outcomes

Probability of getting 1st friend from kindergarten = 4/10

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Since all these probabilities are independent, We can use Multiplicative identity.  Thus,

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Answer:

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Step-by-step explanation:

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By substituting these values to the equation above,

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Therefore,

The answer is 6x^{3} +39x^{2}+54x


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3 years ago
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