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3 years ago

There are 8 people on the debate team. In how many ways can the coach choose 4 members to send to competition?

Mathematics

2 answers:

seropon [69]3 years ago

8 0

Answer:

Step-by-step explanation:

Given : There are 8 people on the debate team.

To Find: In how many ways can the coach choose 4 members to send to competition?

Solution:

We will use combination over here

Formula : $^nC_r=\frac{n!}{r!(n-r)!}$

Now There are 8 people on the debate team and the coach have to choose 4

So, n = 8

r = 4

So, number of ways of choosing 4 people out of 8 = $^8C_4$

= $\frac{8!}{4!(8-4)!}$

= $\frac{8!}{4!4!}$

= $70$

Hence there are 70 ways of choosing 4 members out of 8 to send to competition

meriva3 years ago

4 0

he can either send one half or the other half.

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Aleks04 [339]

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