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3 years ago

11

Yolanda's club has 35 members. its rules require that 60% of them must be present for any vote. at least how many members must b

e present to have a vote?

1 answer:

german3 years ago

5 0

35 x .6 = 21 so there must be 21 people present to take a vote.

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What is the domain of the graph below?

dimaraw [331]

Answer:

B

Step-by-step explanation:

idk how to explain it but im sorry if i tell u the wrong answer

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Surface area of solid figures

Lilit [14]

Answer:

C. 468mm²

Step-by-step explanation:

The formula for the surface area of rectangular prism is:

$A=2(wl+hl+hw)$

Let's break down our variables.

L = 12mm

W = 6mm

H = 7mm + 2mm = 9mm

Now we substitute our values in the formula:

$A=2((6)(12)+(9)(12)+(9)(6))$

$A=2(72+108+54)$

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$A=468mm^{2}$

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3 years ago

6 x (8 - 3) = (? x 8) - (? x 3) what are the answers for the question marks?

Elina [12.6K]

6 x (8 - 3) =

(6 x 8) - (6 x 3)

The answer is 6

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3 years ago

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Which of the equations below could be the equation of this parabola?

nirvana33 [79]

Answer:

$y=-4x^2$ is the equation of this parabola.

Step-by-step explanation:

Let us consider the equation

$y=-4x^2$

$\mathrm{Domain\:of\:}\:-4x^2\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:$

$\mathrm{Range\:of\:}-4x^2:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\le \:0\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:0]\end{bmatrix}$

$\mathrm{Axis\:interception\:points\:of}\:-4x^2:\quad \mathrm{X\:Intercepts}:\:\left(0,\:0\right),\:\mathrm{Y\:Intercepts}:\:\left(0,\:0\right)$

As

$\mathrm{The\:vertex\:of\:an\:up-down\:facing\:parabola\:of\:the\:form}\:y=a\left(x-m\right)\left(x-n\right)$

$\mathrm{is\:the\:average\:of\:the\:zeros}\:x_v=\frac{m+n}{2}$

$y=-4x^2$

$\mathrm{The\:parabola\:params\:are:}$

$a=-4,\:m=0,\:n=0$

$x_v=\frac{m+n}{2}$

$x_v=\frac{0+0}{2}$

$x_v=0$

$\mathrm{Plug\:in}\:\:x_v=0\:\mathrm{to\:find\:the}\:y_v\:\mathrm{value}$

$y_v=-4\cdot \:0^2$

$y_v=0$

Therefore, the parabola vertex is

$\left(0,\:0\right)$

$\mathrm{If}\:a$

$\mathrm{If}\:a>0,\:\mathrm{then\:the\:vertex\:is\:a\:minimum\:value}$

$a=-4$

$\mathrm{Maximum}\space\left(0,\:0\right)$

so,

$\mathrm{Vertex\:of}\:-4x^2:\quad \mathrm{Maximum}\space\left(0,\:0\right)$

Therefore, $y=-4x^2$ is the equation of this parabola. The graph is also attached.

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Help ???????????????????????

Likurg_2 [28]

Answer:

I dont remember how to do this but i wish you luck, try searching on khan academy for how to do this ;)

Step-by-step explanation:

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