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Oksanka [162]
3 years ago
5

1. If the ratio of the ages of Kissi and Esinam is 3:5 and that of Esinam and Lariba is 3:5 and

Mathematics
1 answer:
zloy xaker [14]3 years ago
4 0

Answer:

1) 48 years.

2) Question incorrect.

11 isn't a factor of 64, and 368 isn't a multiple of 64. 11 also isn't a factor of 368, hence, it would be impossible to find the unknown second number with all of these false information in the question.

Step-by-step explanation:

Let the ages of Kissi, Esinam and Lariba be x, y and z respectively.

Ratio of the ages of Kissi and Esinam is 3:5

x:y = 3:5

(x/y) = (3/5)

5x = 3y

x = (3y/5) (eqn 1)

Ratio of the ages of Esinam and Lariba is 3:5

y:z = 3:5

(y/z) = (3/5)

5y = 3z

z = (5y/3) (eqn 2)

The sum of their 3 ages is 147

x + y + z = 147 (eqn 3)

Substituting the values of x and z from eqn 1 and 2 into eqn 3, we have

(3y/5) + y + (5y/3) = 147

(49y/15) = 147

y = (147×15/49) = 45.

x = (3y/5) = (3×45/5) = 27

z = (5y/3) = (5×45/3) = 75

The ages of Kissi, Esinam and Lariba are then 27, 45 and 75 respectively.

The difference in the ages of the oldest amf the youngest is thus, 75 - 27 = 48 years.

2) This question seems to be faulty and incorrect as 11 isn't a factor of 64, and 368 isn't a multiple of 64. 11 also isn't a factor of 368, hence, it would be impossible to find the unknown second number with all of these false information in the question.

Hope this Helps!!!

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