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olasank [31]
3 years ago
12

If f (1) = 5, then (1, 5) is an ordered pair of function f . True False

Mathematics
1 answer:
makkiz [27]3 years ago
5 0

Answer:

true

Step-by-step explanation:

i hope that helped you

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You have a shelf that holds 25 1/2 pounds. What is the most number of 1 1/4 pound books that the shelf can hold?​
patriot [66]

Answer:

20 books

Step-by-step explanation:

given that the shelf can hold 25 1/2 lbs (i.e 25.5 lbs), and that each book weighs 1 1/4 ln (i.e 1.25 lbs)

number of books which the shelf can hold

= weight that the shelf can hold ÷ weight of each book

= 25.5 ÷ 1.25

= 20.4 books

because having 0.4 of a book (i.e part of a book) would not be very feasable, we have to round the number of books down to the nearest whole number)

20.4 books rounded down to nearest whole number = 20 books (answer)

5 0
3 years ago
Read 2 more answers
An oil company fills 1/10 of a tank in 1/4 hour. At this rate, which expression can be used to determine how long it will take f
irina [24]
I'm not 100% sur what it is asking but I think the expression would be
 
15 min. * 10 = min. till the tank is full
6 0
3 years ago
What is the value of x to the nearest tenth?
jenyasd209 [6]
The segment of length x bisects the chord of length 19.2.
The diameter is 24, so the radius is 12.
You have a right triangle with hypotenuse 12, and one leg 19.2/2 = 9.6

9.6^2 + x^2 = 12^2

92.16 + x^2 = 144

x^2 = 51.84

x = 7.2
3 0
3 years ago
The population of a particular country was 26 million in 1981; in 1990, it was 31 million. the exponential growth function descr
yuradex [85]
Just use syblol it is verygood for varible form 
5 0
3 years ago
A particle, initially at rest, moves along the x-axis such that its acceleration at time t > 0 is given by a(t) = 6cos(t). At
Rom4ik [11]

a. By the fundamental theorem of calculus, the velocity function is

v(t)=v(0)+\displaystyle\int_0^ta(u)\,\mathrm du

The particle starts at rest, so v(0)=0, and we have

v(t)=\displaystyle\int_0^t6\cos u\,\mathrm du=6\sin u\bigg|_0^t=6\sin t

Then the position function is

x(t)=\displaystyle x(0)+\int_0^tv(u)\,\mathrm du

with x(0)=6, so

x(t)=6+\displaystyle\int_0^t6\sin u\,\mathrm du=6-6\cos u\bigg|_0^t=12-6\cos t

b. The particle is at rest whenever v(t)=0; this happens for

6\sin t=0\implies \sin t=0\implies t=n\pi

where n is any integer.

3 0
3 years ago
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