Answer:
Roughly speaking, in a normal distribution, a score that is 1 s.d. above the mean is equivalent to the 84th percentile. ... In other words, roughly 95 percent of students are within two standard deviations – positive or negative – of the average
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Simple Interest = Principal * Interest Rate * Term
Total Amount = Principal + Simple Interest
<span>
<span>
</span><span><span>
# Principal Interest rate term Interest Total balance
</span><span> 1
<span> 100.00 </span>6% 1
<span> 6.00 </span>
<span> 106.00
</span></span><span> 3
<span> 100.00 </span>6% 2
<span> 12.00 </span>
<span> 112.00
</span></span><span> 5
<span> 100.00 </span>6% 3
<span> 18.00 </span>
<span> 118.00
</span></span><span> 7
<span> 100.00 </span>6% 4
<span> 24.00 </span>
<span> 124.00
</span></span><span> 9
<span> 3,000.00 </span>5% 3
<span> 450.00 </span>
<span> 3,450.00
</span></span><span>10
<span> 4,000.00 </span>6% 3
<span> 720.00 </span>
<span> 4,720.00
</span></span><span>11
<span> 10,000.00 </span>4% 3
<span> 1,200.00 </span>
<span> 11,200.00
</span></span><span>13
<span> 10,000.00 </span>6% 4
<span> 2,400.00 </span>
<span> 12,400.00
</span></span><span>14
<span> 10,000.00 </span>6% 5
<span> 3,000.00 </span>
<span> 13,000.00 </span>
</span></span></span>
Answer:
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