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asambeis [7]
3 years ago
11

Helpppppppp as soon as possible

Mathematics
2 answers:
eimsori [14]3 years ago
6 0

Answer:

1st one is pandemic

2nd is epidemic

Step-by-step explanation:

Levart [38]3 years ago
5 0

Answer:

pandemic, epidemic.

Step-by-step explanation:

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I need help solving this problem please I would like short explanations please its more helpful for me. :) ​
Allisa [31]

Answer:

First point goes on -2

Step-by-step explanation:

3 0
3 years ago
Alan, Bianca, and Charles are counting in turn. Alan says "one," Bianca says "two," and Charles says "three." Then it's Alan's t
timama [110]
Bianca would say fifty nine
8 0
3 years ago
Verify this trig function. <br> tanysiny = secy-cosy ?
avanturin [10]
LHS\\ \\ =\tan { y } \sin { y } \\ \\ =\frac { \sin { y }  }{ \cos { y }  } \cdot \sin { y }

\\ \\ =\frac { \sin ^{ 2 }{ y }  }{ \cos { y }  } \\ \\ =\frac { 1-\cos ^{ 2 }{ y }  }{ \cos { y }  }

\\ \\ =\frac { 1 }{ \cos { y }  } -\frac { \cos ^{ 2 }{ y }  }{ \cos { y }  } \\ \\ =\sec { y } -\cos { y } \\ \\ =RHS
6 0
3 years ago
If the measure of angle A is 27 degrees, what is the measure of angle 'B'?
timama [110]

Answer:

i'm pretty sure that it is 27 due to vertical angle theorem

let me know if its right :)

Step-by-step explanation:

4 0
3 years ago
An activity has an optimistic time estimate of 25 days, a most likely estimate of 29 days, and a pessimistic estimate of 34 days
Margaret [11]

The expected duration of the activity is 29 days and 4 hours.

Step-by-step explanation:

Step 1:

The optimistic time, t_{o} = 25 days,

The most likely estimate, t_{m} = 29 days.

The pessimistic time, t_{p} = 34 days.

According to PERT, the expected duration of the activity, t_{e} = \frac{t_{0}+4t_{m} +t_{p}  }{6}.

Step 2:

By substituting the given values, we gett_{e} = \frac{t_{0}+4t_{m} +t_{p}  }{6} = t_{e} = \frac{25+4(29) +34  }{6} = \frac{175}{6} = 29.1666.

0.1666 days = 0.1666 (24) = 3.9999 hours.

29.1666 days approximately equal 29 days and 4 hours.

8 0
3 years ago
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