All categories

3 years ago

Solve for x:

Mathematics

1 answer:

elixir [45]3 years ago

4 0

I’m going to say multiply both sides by a which gives you:

a^2-ab-a=2

If not give me a call

You might be interested in

The members of a book club spend the same amount of money for refreshments at each meeting. At one meeting they bought 6 bagels

Tom [10]

The members of a book club spend $0.4 for each Bagel as refreshment.

Let x represent the cost of each bagel.

At a meeting, they bought 6 bagels and spent $9.00 on beverages, hence:

Cost = 6x + 9

At another meeting, they bought 8 bagels and spent $8.20 on beverages, hence:

Cost = 8x + 8.20

Since the same money is spent on each meeting, hence:

6x + 9 = 8x + 8.2

2x = 0.8

x = $0.4

Therefore the cost of each bagel is $0.4

Find out more at: brainly.com/question/13911928

8 0

2 years ago

Suppose your friend's parents invest 15,000 in an account paying 7% compounded annually. What will the balance be after 5 year

meriva

Answer:

FV= $21,038.28

Step-by-step explanation:

Giving the following information:

Initial investment (PV)= $15,000

Interest rate (i)= 7% compounded annually

Number of periods (n)= 5

To calculate the future value (FV), we need to use the following formula:

FV= PV*(1 + i)^n

FV= 15,000*(1.07^5)

FV= $21,038.28

6 0

2 years ago

What is the measure of x? Please help!

Zepler [3.9K]

Answer:

x =√[y²+(27)²] = √[ z² - 3² +(27)²]

Step-by-step explanation:

step 1) x=√[y²+(27)²]

step 2)

We find y

z²=y²+3² → y² = z² - 3²

step 3) x = √[ z² - 3² +(27)²]

7 0

3 years ago

Find the least common multiple (LCM) of 8y^6+ 144y^5+ 640y^4 and 2y^4 + 40y^3 + 200y^2.

Mice21 [21]

Answer:

LCM = $8y^{4}(y+ 10)^{2}(y + 8)$

Step-by-step explanation:

Making factors of $8y^{6}+ 144y^{5}+ 640y^{4}$

Taking $8y^{4}$ common:

$\Rightarrow 8y^{4} (y^{2}+ 18y+ 80)$

Using factorization method:

$\Rightarrow 8y^{4} (y^{2}+ 10y + 8y + 80)\\\Rightarrow 8y^{4} (y (y+ 10) + 8(y + 10))\\\Rightarrow 8y^{4} (y+ 10)(y + 8))\\\Rightarrow \underline{2y^{2}} \times 4y^{2} \underline{(y+ 10)}(y + 8)) ..... (1)$

Now, Making factors of $2y^{4} + 40y^{3} + 200y^{2}$

Taking $2y^{2}$ common:

$\Rightarrow 2y^{2} (y^{2}+ 20y+ 100)$

Using factorization method:

$\Rightarrow 2y^{2} (y^{2}+ 10y+ 10y+ 100)\\\Rightarrow 2y^{2} (y (y+ 10) + 10(y + 10))\\\Rightarrow \underline {2y^{2} (y+ 10)}(y + 10) ............ (2)$

The underlined parts show the Highest Common Factor(HCF).

i.e. HCF is $2y^{2} (y+ 10)$ .

We know the relation between LCM, HCF of the two numbers 'p' , 'q' and the numbers themselves as:

$HCF \times LCM = p \times q$

Using equations (1) and (2): $\Rightarrow 2y^{2} (y+ 10) \times LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times 2y^{2} (y+ 10)(y + 10)\\\Rightarrow LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times (y + 10)\\\Rightarrow LCM = 8y^{4}(y+ 10)^{2}(y + 8)$

Hence, LCM = $8y^{4}(y+ 10)^{2}(y + 8)$

5 0

3 years ago

Factor 64v^3 + 192v^2 -56v - 168

Kaylis [27]

Hello from MrBillDoesMath!

Answer:

8(v+3) ( -1/2 (sqrt(14) - 4 v) (4 v + sqrt(14)) )

Discussion:

Given

64v^3 + 192v^2 - 56 v - 168

Factor 64v^2 from the first two terms. Factor 56 from the last two terms:

64v^2(v+3) - 56(v + 3) => factor (v+3) from both terms

(v+3) (64v^2 - 56) => factor 8 from both terms in the right ()

8(v+3)(8v^2-7) => factor 8y^2-7

8(v+3) ( -1/2 (sqrt(14) - 4 v) (4 v + sqrt(14)) )

Thank you,

MrB

4 0

3 years ago