What single decimal multiplier would you use to increase by 2% followed by a 1% increase?
1 answer:
You might be interested in
Water that weighs 325 lbs will fill 5.2 cubic feet.
Step-by-step explanation:
This is a simple question of cross multiplication
<u>DATA:</u>
<em>1. The weight of water for 1 cubic feet is 62.5</em>
<em>2. The weight of water for 'X' cubic feet is 325 </em>
<em>3. To find x, form an equation:</em>
Cubic feet : Weight of water
1 : 62.5
X : 325
<em>4. Cross multiply</em>
X x 62.5 = 1 x 325
62.5X = 325
<em>5. Make X the subject</em>
X =
<em>6. Solve to find X</em>
X = 5.2 cubic feet
Therefore, water that weighs 325 lbs will fill 5.2 cubic feet.
Key words: Conversion
Learn more about conversions at
#LearnwithBrainly
9514 1404 393
Answer:
possible rational roots: ±{1/3, 2/3, 1, 4/3, 2, 3, 4, 6, 12}
actual roots: -1, (2 ±4i√2)/3
no turning points; no local extrema
end behavior is same-sign as x-value end-behavior
Step-by-step explanation:
The Fundamental Theorem tells us this 3rd-degree polynomial will have 3 roots.
The Rational Root Theorem tells us any rational roots will be of the form ...
±{factor of 12}/{factor of 3} = ±{1, 2, 3, 4, 6, 12}/{1, 3}
= ±{1/3, 2/3, 1, 4/3, 2, 3, 4, 6, 12} . . . possible rational roots
Descartes' Rule of Signs tells us the two sign changes mean there will be 0 or 2 positive real roots. Changing signs on the odd-degree terms makes the sign-change count go to 1, so we know there is one negative real root.
The y-intercept is 12. The sum of all coefficients is 22, so f(1) > f(0) and there are no positive real roots in the interval [0, 1]. Synthetic division by x-1 shows the remainder is 22 (which we knew) and all the quotient coefficients are all positive. This means x=0 is an upper bound on the real roots.
The sum of odd-degree coefficients is 3+8=11, equal to the sum of even-degree coefficients, -1+12=11. This means that -1 is a real root. Synthetic division by x+1 shows the remainder is zero (which we knew) and the quotient coefficients alternate signs. This means x=-1 is a lower bound on real roots. The quotient of 3x^2 -4x +12 is a quadratic factor of f(x):
f(x) = (x +1)(3x^2 -4x +12)
The complex roots of the quadratic can be found using the quadratic formula:
x = (-(-4) ±√((-4)^2 -4(3)(12)))/(2(3)) = (4 ± √-128)/6
x = (2 ± 4i√2)/3 . . . . complex roots
__
The graph in the third attachment (red) shows there are no turning points, hence no relative extrema. The end behavior, as for any odd-degree polynomial with a positive leading coefficient, is down to the left and up to the right.
