Answer:
a) 30 kangaroos in 2030
b) decreasing 8% per year
c) large t results in fractional kangaroos: P(100) ≈ 1/55 kangaroo
Step-by-step explanation:
We assume your equation is supposed to be ...
P(t) = 76(0.92^t)
__
a) P(10) = 76(0.92^10) = 76(0.4344) = 30.01 ≈ 30
In the year 2030, the population of kangaroos in the province is modeled to be 30.
__
b) The population is decreasing. The base 0.92 of the exponent t is the cause. The population is changing by 0.92 -1 = -0.08 = -8% each year.
The population is decreasing by 8% each year.
__
c) The model loses its value once the population drops below 1/2 kangaroo. For large values of t, it predicts only fractional kangaroos, hence is not realistic.
P(100) = 75(0.92^100) = 76(0.0002392)
P(100) ≈ 0.0182, about 1/55th of a kangaroo
After demonstrating the procedure by algebraic means, the expression
<em>is equivalent to</em>
.
In this question we proceed to <em>simplify</em>
by <em>algebraic</em> means into a <em>single</em> <em>radical</em> expression when possible, whose procedure is shown below and explained by appropriate definitions and theorems:
-
Given. -
Commutative property/ Associative property. -
Definition of cubic root/
/Result
After demonstrating the procedure by algebraic means, the expression
<em>is equivalent to</em>
.
To learn more on radical expressions, we kindly invite to check this verified question: brainly.com/question/1810591
F(x) = 3x²-6x+2
f(2) = ?
f(2) = 3.2²-6.2+2
f(2) = 3.4-12+2
f(2) = 12-12+2
f(2) = 2
A) 2✔
Answer:
-3
Step-by-step explanation:
3x-1=-10
3x=-9
x=-3
Answer:
This problem was pasted incorrectly
Step-by-step explanation: