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weqwewe [10]
3 years ago
9

By construction copy the angles given leave all construction arcs in your final figure

Mathematics
2 answers:
sashaice [31]3 years ago
7 0

Angles in the file below:)

Download pdf
DochEvi [55]3 years ago
5 0
I don’t know what you are trying to ask. Is there and image?
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Calculate the volume of the figure.
Margarita [4]

Answer:

Step-by-step explanation:

Formula

Volume = L * w * h

Givens

L = 7 feet

w = 4 feet

h = 5 feet

Solution

V = L * w * h             Substitute values into the formula

V = 7 * 4 * 5

V = 140 cubic feet.

Answer

140 ft^3

8 0
3 years ago
Read 2 more answers
Evaluate.<br><br> 4^3−4÷2⋅5<br><br><br> 20<br><br> 40<br><br> 54<br><br> 150
nika2105 [10]

Answer:

150

Step-by-step explanation:

1. 4^3 = 4 x 4 x 4 = 16 x 4 = 64

2. 64 - 4 = 60

3. 60 ÷ 2 = 30

4. 30 ⋅ 5 = 150

3 0
3 years ago
2. Sam ran to the mall and back to quickly pick up a small
Aleonysh [2.5K]

Answer:

I think the answer is 47

Step-by-step explanation:

6 0
3 years ago
Which expression is equivalent to 1.5 raised to the fifth power divided by 0.7 raised to the fourth power, all raised to the thi
harina [27]

The expression which is equivalent to the given expression as in the task content is; 1.5 raised to the fifteenth power divided by 0.7 raised to the twelfth power.

<h3>What is the expression which is equivalent to the given expression?</h3>

According to the task content, it follows that the expression given is;

(1.5⁵/0.7⁴)³

= 1.5^(3×5) /0.7^(4×3)

= 1.5¹⁵/0.7¹².

Hence, the expression which is equivalent is; 1.5 raised to the fifteenth power divided by 0.7 raised to the twelfth power.

Read more on exponents;

brainly.com/question/847241

#SPJ1

4 0
1 year ago
Read 2 more answers
Find lim ?x approaches 0 f(x+?x)-f(x)/?x where f(x) = 4x-3
Whitepunk [10]

If f(x)=4x-3:

\displaystyle\lim_{\Delta x\to0}\frac{(4(x+\Delta x)-3)-(4x-3)}{\Delta x}=\lim_{\Delta x\to0}\frac{4\Delta x}{\Delta x}=4

If f(x)=4x^{-3}:

\displaystyle\lim_{\Delta x\to0}\frac{\frac4{(x+\Delta x)^3}-\frac4{x^3}}{\Delta x}=\lim_{\Delta x\to0}\frac{\frac{4x^3-4(x+\Delta x)^3}{x^3(x+\Delta x)^3}}{\Delta x}

\displaystyle=\lim_{\Delta x\to0}\frac{4x^3-4(x^3+3x^2\Delta x+3x(\Delta x)^2+(\Delta x)^3)}{x^3\Delta x(x+\Delta x)^3}

\displaystyle=\lim_{\Delta x\to0}\frac{-12x^2\Delta x-12x(\Delta x)^2-4(\Delta x)^3}{x^3\Delta x(x+\Delta x)^3}=-\frac{12}{x^4}

7 0
4 years ago
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