Answer:
One way to find the least common multiple of two numbers is to first list the prime factors of each number. Then multiply each factor the greatest number of times it occurs in either number. If the same factor occurs more than once in both numbers, you multiply the factor the greatest number of times it occurs.
Step-by-step explanation:
The choices are:
A)
2x - 15 ≤ 4y
B)
2x - 15 ≥ 4y
C)
15 - 2x ≤ 4y
D)
<span>15 - 2x ≥ 4y
</span>
Therefore, the best and most correct answer among the choices provided by the question is the fourth choice "<span>15 - 2x ≥ 4y". </span>I hope my answer has come to your help. God bless and have a nice day ahead!
Answer:
Step-by-step explanation:
arithmetic sequence formula: 
where 
is the first term and 
is the common difference
Given:
⇒ 
⇒ 
Given:
⇒ 
⇒ 
Rearrange the first equation to make the subject:
a = 32 - 9d
Now substitute into the second equation and solve for
(32 - 9d) + 11d = 106
⇒ 32 + 2d = 106
⇒ 2d = 106 - 32 = 74
⇒ d = 74 ÷ 2 = 37
Substitute found value of into the first equation and solve for :
a + (9 x 37) = 32
a + 333 = 32
a = 32 - 333 = -301
Therefore, the equation is:
Answer:
I honestly have no clue. Sorry I cant help you
Step-by-step explanation:
Probaility in general is defined as the ratio of positive outcomes over the total number of outcomes.
In the first example, the total outcomes are 16; let us count the positive ones. There are 8 even numbers from 1-16. The prime numbers are 2,3,5,7,11,13. Out of those, only 5 are odd. Hence, in total there are 13 positive outcomes. Thus, the probability is 13/16=81.25%
Let's restrict the problem to the students that studied for the exam; the proportion is 0.57 of the total students. 0.52 of the total students studied and saw an increase in their exam. Hence, the probability that a student who studied saw an increse is 0.52/0.57 (here a positive outcome is the proportion that saw an increase and the total outcomes are all the students that studied). 0.52/0.57=91.22%
