How can you use a model to tell a percentage as a fraction with a denominator of 100?

Aileen can read 1.5 pages for every page her friend can read. Aileen's mom was very excited and she said to Aileen: "So, if your

Strike441 [17]

1.5 pages her friend can read so the formula would be

1.5x and x being the number of pages her friend reads

1.5 times 20 is not 25 it's 30

therefore no Aileen's mom is not correct

3 0

3 years ago

Read 2 more answers

Andrea wanted to calculate 5% of 300, so she multiplied 300 by 0.5 (300 x 0.5).

Mars2501 [29]

This is because Andrea converted the Percentage wrong.
to Convert a Percent to a Decimal, she should have divided by 100
so 5 divided by 100 = 0.05 [not 0.5]
Andrea should have multiplied 300 by 0.05 instead to get the right answer

quickly finding 10% of a number means to simply move the decimal to the left one place
so 10% of 300 is 30

since 5% is half of 10%
half of 30 is 15

and so 5% of 300 is 15

5 0

3 years ago

Please help? I’m super lost...

babunello [35]

Answer:

Step-by-step explanation:

In all of these problems, the key is to remember that you can undo a trig function by taking the inverse of that function. Watch and see.

a. $sin2\theta =-\frac{\sqrt{3} }{2}$

Take the inverse sin of both sides. When you do that, you are left with just 2theta on the left. That's why you do this.

$sin^{-1}(sin2\theta)=sin^{-1}(-\frac{\sqrt{3} }{2} )$

This simplifies to

$2\theta=sin^{-1}(-\frac{\sqrt{3} }{2} )$

We look to the unit circle to see which values of theta give us a sin of -square root of 3 over 2. Those are:

$2\theta =\frac{5\pi }{6}$ and

$2\theta=\frac{7\pi }{6}$

Divide both sides by 2 in both of those equations to get that values of theta are:

$\theta=\frac{5\pi }{12},\frac{7\pi }{12}$

b. $tan(7a)=1$

Take the inverse tangent of both sides:

$tan^{-1}(tan(7a))=tan^{-1}(1)$

Taking the inverse tangent of the tangent on the left leaves us with just 7a. This simplifies to

$7a=tan^{-1}(1)$

We look to the unit circle to find which values of <em>a</em> give us a tangent of 1. They are:

$7\alpha =\frac{5\pi }{4},7\alpha =\frac{\pi }{4}$

Dibide each of those equations by 7 to find that the values of alpha are:

$\alpha =\frac{5\pi}{28},\frac{\pi}{28}$

c. $cos(3\beta)=\frac{1}{2}$

Take the inverse cosine of each side. The inverse cosine and cosine undo each other, leaving us with just 3beta on the left, just like in the previous problems. That simplifies to:

$3\beta=cos^{-1}(\frac{1}{2})$