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velikii [3]
3 years ago
10

Nitrogen has five valence electrons. What is the correct Lewis structure for nitrogen?

Chemistry
2 answers:
alexandr402 [8]3 years ago
3 0
An N with 5 dots around it

swat323 years ago
3 0

Answer :

Lewis-dot structure : The number of valence electrons are represented in the Lewis-dot structure by the dot. It shows the bonding between the atoms of a the molecule and it also shows the unpaired electrons present in the molecule.

The number of valence electrons in nitrogen is, 5

The Lewis-dot structure of nitrogen is shown below.

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Mekhanik [1.2K]

Answer:

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Explanation:

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8 0
3 years ago
A sample of seawater weighs 250 g and has a volume of 173 ml. What is the density of seawater?
kari74 [83]

Answer:

<h2>The answer is 1.45 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}  \\

From the question

mass of seawater = 250 g

volume = 173 mL

It's density is

density =  \frac{250}{173}  \\  = 1.4450867052...

We have the final answer as

<h3>1.45 g/mL</h3>

Hope this helps you

8 0
3 years ago
Which of the following is true of carbon?
pashok25 [27]
I’m pretty sure it’s A or C
8 0
3 years ago
Read 2 more answers
Of the following which element is the heaviest? helium argon lithium aluminum
Georgia [21]

Answer:

Lithium

Explanation:

it is the only metal listed.

5 0
4 years ago
A closed system initially containing 1×10^-3 hydrogen 2×10^-3M iodine at 448 degree Celsius and is allowed to reach equilibrium.
GaryK [48]

Answer:

Kc = 50.5

Explanation:

We determine the reaction:

H₂  +  I₂   ⇄   2HI

Initially we have 0.001 molesof H₂

and 0.002 moles of I₂

If we have produced 0.00187 moles of HI in the equilibrium we have to know, how many moles of I₂ and H₂, have reacted.

           H₂     +      I₂      ⇄   2HI

In:     0.001       0.002           -

R:       x                 x                2x

Eq:  0.001-x    0.002-x      0.00187  

x = 0.00187/2 = 9.35×10⁻⁴ moles that have reacted

So in the equilibrium we have:

0.001 - 9.35×10⁻⁴ = 6.5×10⁻⁵  moles of H₂

0.002 - 9.35×10⁻⁴ = 1.065×10⁻³ moles of I₂

Expression for Kc is =  (HI)² / (H₂) . (I₂)

0.00187 ² /  6.5×10⁻⁵ . 1.065×10⁻³ = 50.5

5 0
3 years ago
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