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masya89 [10]
3 years ago
5

I am in desperate need of help will give 40 points to whoever helps me!!!!! I have a quiz tomorrow but I have no idea how to do

these practice problems. I know u have to use the boiling and freezing pint formula but i don't know how to plug them in because these problems all look different and asks for different things

Chemistry
1 answer:
serious [3.7K]3 years ago
5 0
All of the questions here are pertaining to the colligative properties of a solution and the preparation of solutions. Maybe, it would be best if you understand the equations to be used in order to answer these questions.<span>
Freezing point depression or Boiling point elevation:

</span><span>ΔT = -K (m) (i)

</span>ΔT is the change in the freezing point or the boiling point not the freezing point/boiling point. Therefore, it should be added to the original value of the property of the solvent. 
<span>
K is a constant called the molal freezing point depression constant and for the boiling point is the boiling point elevation constant. It is a property of the solvent. 
</span><span>
m is the concentration of the solute in the solvent in terms of molality or kg solute/kg solvent. 
</span><span>
i is the vant hoff factor which will represent the number of ions which the solute dissociates when in solution.</span>
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a helium balloon has a volume of 2.95 liters at 25 c. the volume of the ballon decreased to 2.25 l after it is placed outside on
OleMash [197]

Answer:

The outside temperature is -45.8°C

Explanation:

When a gas keeps on constant its moles and its pressure, we can assume that volume will be increased or decreased as the T° (absolute T° in K).

V1 / T1 = V2 / T2

2.95L/298K = 2.25L / T2

(2.95L/298K ) . T2 = 2.25L

T2 = 2.25L . 298K / 2.95L

T2 = 227.2K

T°K - 273 = T°C

227.2K - 273 = -45.8°C

3 0
3 years ago
A balloon, whose volume at 23°C is 535 mL, is heated to 46°C. Assuming the pressure and amount of gas remain constant, what is t
NikAS [45]
This problem requires a certain equation.  That equation is V1/T1=V2/T2, where V1 is your initial volume (535 mL in this case), T1 is your initial temperature in Kelvin(23 degrees C = 296 K), V2 is your final volume (unknown), and T2 is your final temperature (46 degrees C = 319 K). By plugging in these values, the equation looks like this: 535/296=V2/319.  Now multiply both sides of the equation by 319, and your final answer is V2= 576.6 mL
5 0
3 years ago
Read 2 more answers
2) Which liberates the most energy?
evablogger [386]

Answer: F(g)+e^-\rightarrow F^-(g)

Explanation:

Electron gain enthalpy is defined as energy released on addition of electron to an isolated gaseous atom.  

The amount of energy released will be maximum when the tendency to attract electrons is maximum. As flourine has atomic number of 9 and has electronic configuration of 2,7. It can readily gain 1 electron to attain stable noble gas configuration and hence liberates maximum energy.

F(g)+e^-\rightarrow F^-(g)

4 0
3 years ago
The mass and volume of each box is given in the chart below. Calculate the density of each box. Density = Mass/ volume which box
stira [4]

Box C will have the greatest density.

All boxes have the same volume.

Explanation:

We calculate the density using the following formula:

density = mass / volume

density of Box A = 10 g / 20 cm³ = 0.5 g/cm³

density of Box B = 30 g / 20 cm³ = 1.5 g/cm³

density of Box C = 170 g / 20 cm³ = 8.5 g/cm³

Box C will have the greatest density.

All boxes have the same volume.

Learn more about:

density

brainly.com/question/952755

#learnwithBrainly

7 0
3 years ago
when 48 .0g of carbon reacts with oxygen gas to form carbon dioxide, no carbon or oxygen is left over. How much oxygen is reacte
Arte-miy333 [17]

Answer:

128g

Explanation:

Given parameters:

Mass of carbon  = 48g

Mass of carbon dioxide  = 176g

Unknown:

Mass of oxygen that reacted  = ?

Solution:

Every chemical reaction must obey the law of conservation of mass. It states that "in a chemical reaction, matter is neither created nor destroyed" .

So;

     Mass of carbon + Mass of oxygen  = Mass of carbon dioxide

Mass of oxygen  = Mass of carbon dioxide  - Mass of carbon

Mass of oxygen  = 176  - 48  = 128g

3 0
3 years ago
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