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blagie [28]
3 years ago
8

1. Calculate how many moles of glycine are in a 130.0-g sample of glycine.2. Calculate the percent nitrogen by mass in glycine.

Chemistry
1 answer:
Alexxx [7]3 years ago
4 0

Answer:

n=1.732mol

\% N=18.7\%

Explanation:

Hello!

In this case, since the molecular formula of glycine is C₂H₅NO₂, we realize that the molar mass is 75.07 g/mol; thus, the moles in 130.0 g of glycine are:

n=130.0g*\frac{1mol}{75.07 g}\\\\ n=1.732mol

Furthermore, we can notice 75.07 grams of glycine contains 14.01 grams of nitrogen; thus, the percent nitrogen turns out:

\% N=\frac{14.01}{75.07}*100\% \\\\\% N=18.7\%

Best regards!

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If you have 220 liters O2 at STP how many moles of O2 do you have
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4 0
3 years ago
For the following reaction, 5.78 grams of chlorine gas are mixed with excess iron. The reaction yields 6.79 grams of iron(III) c
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Answer:

a. Theoretical yield = 8.81 g

b. 77 %

Explanation:

We begin from the reaction:

2Fe (s) + 3Cl₂ (g) → 2FeCl₃ (s)

and the excess is the iron, so the limiting reagent is the chlorine.

We convert mass to moles → 5.78 g / 70.90 g/mol = 0.0815 mol

Ratio is 3:2 so we think this:

From 3 moles of chlorine, I can produce 2 moles of Iron (III) chloride

Then 0.0815 moles would produce (0.0815 . 2) /3 = 0.0543 moles

This is the theoretical yield. We convert the moles to mass:

0.0543 mol . 162.2 g /mol = 8.81 g

If the reaction yields 6.79 g of FeCl₃ and the theoretical yield is 8.81 g ,we can obtain the percent yield: (6.79 / 8.81) . 100 = 77 %

5 0
3 years ago
10) Explain what arsenic had to do with preserving bodies in the past and how that related to Sylvester’s body. Tell me how the
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5 0
3 years ago
How many moles are in 43.5 g of sodium hydroxide (NaOH)?
Makovka662 [10]

Answer:

1.09 moles of NaOH

Explanation:

First of all, to calculate moles, you need to find the molar mass of NaOH.

Let us first find the molar mass of NaOH then.

Na = 23.0 amu

O = 16.0

H = 1.0

They are 1 nitrogen atom, 1 oxygen atom, and one hydrogen atom.

So do this.

23.0(1) + 16.0(1) + 1.0(1) = 40 g/mol.

Now use dimensional analysis to show your work

43.5 g of NaOH * 1 mol of NaOH / 40 g/mol of NaOH

The grams cancel out.

43.5 / 40.0 = 1.0875

Use sig figs and round the answer to the nearest hundredths place.

1.0875 = 1.09

So the final answer is 1.09 moles of NaOH

Hope it helped!

3 0
3 years ago
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