Let us assume number of points scored by Team B = b points.
Number of points scored by Team A 5 fewer than twice as many points as Team B, that is "5 less than 2b" = (2b-5) points .
Team C scored 80 more points than Team B, that is " 80 more than b" = (b+80) points.
Total number of points scored by all teams = 983 points.
Therefore, we can setup an equation:
<h3>(2b-5) + b + (b+80) = 983.</h3>
Therefore, an equation to represent this scenario using the variable b to represent Team B’s total points is (2b-5) + b + (b+80) = 983.
Answer:
7n - 1
Step-by-step explanation:
notice that the difference between adjacent terms is 7.
so nth term is given by:
nth term = first term + (n-1)×difference (n is any number)
= 6 + (n-1)7
= 6+ 7n -7
= 7n - 1
hope this helps :-))
50 + (15 × 15), 50 + 15 × 50 + 15, (10 × 5) + 225, 10 × 225 + 5 × 225
Solution:
Given expression is 50 + 225.
To find the equivalent expressions for 50 + 225.
(1) 225 can be written as 15 × 15.
⇒ 50 + 225 = 50 + (15 × 15)
(2) Using distributive law, we find the another equivalent expression
a + (b × c) = a + b × b + c
⇒ 50 + (15 × 15) = 50 + 15 × 50 + 15
(3) Now, 50 can be written as 10 × 5.
⇒ 50 + 225 = (10 × 5) + 225
(4 Using distributive law, we find the another equivalent expression
a + (b × c) = a + b × b + c
⇒ (10 × 5) + 225 = 10 × 225 + 5 × 225
Hence the equivalent expressions for 50 + 225 are:
50 + (15 × 15)
50 + 15 × 50 + 15
(10 × 5) + 225
10 × 225 + 5 × 225
