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Furkat [3]
3 years ago
13

A training field is formed by joining a rectangle and two semicircles, as shown below. The rectangle is 97m long and 66m wide. W

hat is the length of a training track running around the field? (Use the value 3.14 for π, and do not round your answer. Be sure to include the correct unit in your answer.)
Mathematics
1 answer:
Ket [755]3 years ago
3 0

Answer:

401.24m

Step-by-step explanation:

the length is,

97x2 + 66x3.14

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Step-by-step explanation:

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3 years ago
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tigry1 [53]

Answer:

The graduate will have $4,084.97 when he cashes in the CD at the end of the 36-months.

Step-by-step explanation:

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FV = PV * (1 + r)^n ................................. (1)

Where;

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PV = Present value or the total amount invested = Cash gifts from friends and relatives + Amount of 3 scholarships he received = $900 + $250 + $300 + $1,400 = $2,850

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n = number of days = 36 months * 360 days = 12,960

Substituting the values into equation (1), we have:

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HELP I WILL GIVE 5 POINTS TO WHOM EVER CAN ANSWER THESE LAST 2 QUESTIONS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
vodka [1.7K]
Group and factor
undistribute then undistribute again
remember
ab+ac=a(b+c)
this is important



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undistribute 2d
2d(3d^3+2d^2-3d-2)
group insides
2d[(3d^3+2d^2)+(-3d-2)]
undistribute
2d[(d^2)(3d+2)+(-1)(3d+2)]
undistribute the (3d+2) part
(2d)(d^2-1)(3d+2)
factor that difference of  2 perfect squares
(2d)(d-1)(d+1)(3d+2)






77.
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7 0
3 years ago
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