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4 years ago

5

What measurement can be qualitative

1 answer:

shepuryov [24]4 years ago

4 0

How soft one's skin is.

You might be interested in

The gradient of the curve

AleksAgata [21]

Answer:

<u>Coordinate</u><u> </u><u>of</u><u> </u><u>P</u><u> </u><u>is</u><u> </u><u>(</u><u>-</u><u>2</u><u>,</u><u> </u><u>-</u><u>3</u><u>)</u>

Step-by-step explanation:

Gradient is the derivative of the curve:

$y = {3x}^{2} + 11x + 7 \\ \\ \frac{dy}{dx} = 6x + 11$

but dy/dx is -1 :

$6x + 11 = - 1 \\ 6x = - 12 \\ x = - 2$

substitute for x :

$y = 3( - 2) {}^{2} + 11( - 2) + 7 \\ y = - 3$

3 0

3 years ago

Which shows the following expression after the negative exponents have been eliminated? xy^-6/x^-4 y^2, x=/0 y=/0

makvit [3.9K]

The expression would be $\frac{x^5}{y^8}$ after the negative exponents have been removed.

A negative exponent basically tells us to "flip" the side of the fraction it's on. This means that y⁻⁶ on the numerator would go to the denominator, and that x⁻⁴ on the denominator would go to the numerator. This gives us:

$\frac{x\times x^4}{y^2\times y^6}=\frac{x^5}{y^8}$

4 0

4 years ago

Read 2 more answers

Sauron [17]

$\rule{200}4$

Answer : <em>The</em><em> </em><em>required</em><em> </em><em>ratio</em><em> </em><em>is</em><em> </em><em>(</em><em>1</em><em>4</em><em>m</em><em>-</em><em>6</em><em>)</em><em>:</em><em>(</em><em>8</em><em>m</em><em>+</em><em>2</em><em>3</em><em>)</em><em> </em><em>.</em>

$\rule{200}4$

Here we are given that the ratio of sum of first n terms of two AP's is (7n + 1):(4n + 27) .

That is.

$\small\sf\longrightarrow \dfrac{S_1}{S_2}=\dfrac{7n +1}{4n +27} \\$

As , we know that the sum of n terms of an AP is given by ,

$\small\sf\longrightarrow \pink{ S_n =\dfrac{n}{2}[2a +(n-1)d]} \\$

Assume that ,

First term of 1st AP = a
First term of 2nd AP = a'
Common difference of 1st AP = d
Common difference of 2nd AP = d'

Using this we have ,

$\small\sf\longrightarrow \dfrac{S_1}{S_2}=\dfrac{\dfrac{n}{2}[2a + (n-1)d]}{\dfrac{n}{2}[2a' +(n-1)d'] } \\$

$\small\sf\longrightarrow \dfrac{7n+1}{4n+27}=\dfrac{2a + (n -1)d}{2a' + (n -1)d' } . . . . . (i) \\$

Now also we know that the nth term of an AP is given by ,

$\longrightarrow\sf\small \pink{ T_n = a + (n-1)d}\\$

Therefore,

$\longrightarrow\sf\small \dfrac{T_{m_1}}{T_{m_2}}= \dfrac{ a + (n-1)d }{a'+(n-1)d'}. . . . . (ii)\\$

$\longrightarrow\sf\small \dfrac{T_1}{T_2}=\dfrac{2a + (2n-2)d}{2a'+(2n-2)d'} . . . . . (iii)\\$

From equation (i) and (iii) ,

$\longrightarrow\sf\small n-1 = 2m-2\\$

$\longrightarrow\sf\small n = 2m -2+1 \\$

$\longrightarrow\sf\small n = 2m -1 \\$

Substitute this value in equation (i) ,

$\longrightarrow \sf\small \dfrac{2a+ (2m-1-1)d}{2a' +(2m-1-1)d'}=\dfrac{7(2m-1)+1}{4(2m-1) +27}\\$

Simplify,

$\longrightarrow\sf\small \dfrac{ 2a + (2m-2)d}{2a' +(2m-2)d'}=\dfrac{14m-7+1}{8m-4+27}\\$

$\longrightarrow\sf\small \dfrac{2[a + (m-1)d]}{2[a' + (m-1)d']}=\dfrac{ 14m-6}{8m+23}\\$

$\longrightarrow\sf\small \dfrac{[a + (m-1)d]}{[a' + (m-1)d']}=\dfrac{ 14m-6}{8m+23}\\$

From equation (ii) ,

$\longrightarrow\sf\small \underline{\underline{\blue{ \dfrac{T_{m_1}}{T_{m_2}}=\dfrac{ 14m-6}{8m+23}}}}\\$

$\rule{200}4$

8 0

3 years ago

What is another name for the set of counting numbers

Masteriza [31]

Its is called A positive integer or a natural number.

5 0

3 years ago

Rita ran for class president. She received 90 votes in the election. These votes represent 60% of the total number of students i

Sholpan [36]

Answer:

54 students

Step-by-step explanation:

90× 60% = 54

6 0

3 years ago

Read 2 more answers