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maria [59]
3 years ago
8

The gradient of the curve

Mathematics
1 answer:
AleksAgata [21]3 years ago
3 0

Answer:

<u>Coordinate</u><u> </u><u>of</u><u> </u><u>P</u><u> </u><u>is</u><u> </u><u>(</u><u>-</u><u>2</u><u>,</u><u> </u><u>-</u><u>3</u><u>)</u>

Step-by-step explanation:

Gradient is the derivative of the curve:

y = {3x}^{2} + 11x + 7 \\  \\  \frac{dy}{dx}  = 6x + 11

but dy/dx is -1 :

6x + 11 =  -  1 \\ 6x =  - 12 \\ x =  - 2

substitute for x :

y = 3( - 2) {}^{2}  + 11( - 2) + 7 \\ y =   - 3

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The answer is B because for every x input there is a y output
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Given cos = -2/5 a in quadrant III and cos b = 1/4, b in quadrant I find
BigorU [14]

I guess you mean \cos a=-\dfrac25. Since a is in quadrant III, we expect \sin a. Then

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Since b is in quadrant I, we expect \sin b>0, so that

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Now,

\sin(a+b)=\sin a\cos b+\cos a\sin b=-\dfrac{2\sqrt{15}+\sqrt{21}}{20}

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and

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5 0
4 years ago
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0.0008235

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8 0
3 years ago
In a hydroelectricity production, water falls from a dam into a turbine wheel 49 m below. What is the velocity of water at the t
svlad2 [7]

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u is the initial velocity = 0m/s

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v = √960.4

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If line AB is parallel to line RS, find the value of x.
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