All categories

3 years ago

What's another way to do this cuz I'm SAD rn cuz I got a virus on my computer

Mathematics

2 answers:

emmainna [20.7K]3 years ago

3 0

You need to add them all.

Valentin [98]3 years ago

3 0

First, you would do 4 - 3. (4 - 3 = 1)
Next, you would do 1 x 5. (1 x 5 = 5)
Finally, you would do 2 + 5. (2 + 5 = 7)

Hopefully this helps!

You might be interested in

What is a correct name for the angle shown?ROZROLSO ZRTSOZSRTST

Shalnov [3]

Given: Different points and an angles as found in the image

To Determine: The correct name of the angle shown

Solution

An angle is formed when two lines meet at a point. This is as shown below

Let us apply the above to the given image

The angle formed is shown by the red arc.

Hence, the correct name of the angle shown is ∠

7 0

11 months ago

Find x. Round to the nearest tenth if necessary.

Brilliant_brown [7]

Answer:

Step-by-step explanation:

14 times 14 then do 15 times 15 then add both answers up and take that answer and square route it

6 0

2 years ago

La potencia que se obtiene de elevar a un mismo exponente un numero racional y su opuesto es la misma verdadero o falso?

malfutka [58]

Answer:

Falso.

Step-by-step explanation:

Sea $d = \frac{a}{b}$ un número racional, donde $a, b \in \mathbb{R}$ y $b \neq 0$ , su opuesto es un número real $c = -\left(\frac{a}{b} \right)$ . En el caso de elevarse a un exponente dado, hay que comprobar cinco casos:

(a) El exponente es cero.

(b) El exponente es un negativo impar.

(c) El exponente es un negativo par.

(d) El exponente es un positivo impar.

(e) El exponente es un positivo par.

(a) El exponente es cero:

Toda potencia elevada a la cero es igual a uno. En consecuencia, $c = d = 1$ . La proposición es verdadera.

(b) El exponente es un negativo impar:

Considérese las siguientes expresiones:

$d' = d^{-n}$ y $c' = c^{-n}$

Al aplicar las definiciones anteriores y las operaciones del Álgebra de los números reales tenemos el siguiente desarrollo:

$d' = \left(\frac{a}{b} \right)^{-n}$ y $c' = \left[-\left(\frac{a}{b} \right)\right]^{-n}$

$d' = \left(\frac{a}{b} \right)^{(-1)\cdot n}$ y $c' = \left[(-1)\cdot \left(\frac{a}{b} \right)\right]^{(-1)\cdot n}$

$d' = \left[\left(\frac{a}{b} \right)^{-1}\right]^{n}$ y $c' = \left[(-1)^{-1}\cdot \left(\frac{a}{b} \right)^{-1}\right]^{n}$

$d' = \left(\frac{b}{a} \right)^{n}$ y $c = (-1)^{n}\cdot \left(\frac{b}{a} \right)^{n}$

$d' = \left(\frac{b}{a} \right)^{n}$ y $c' = \left[(-1)\cdot \left(\frac{b}{a} \right)\right]^{n}$

$d' = \left(\frac{b}{a} \right)^{n}$ y $c' = \left[-\left(\frac{b}{a} \right)\right]^{n}$

Si $n$ es impar, entonces:

$d' = \left(\frac{b}{a} \right)^{n}$ y $c' = - \left(\frac{b}{a} \right)^{n}$

Puesto que $d' \neq c'$ , la proposición es falsa.

(c) El exponente es un negativo par.

Si $n$ es par, entonces:

$d' = \left(\frac{b}{a} \right)^{n}$ y $c' = \left(\frac{b}{a} \right)^{n}$

Puesto que $d' = c'$ , la proposición es verdadera.

(d) El exponente es un positivo impar.

Considérese las siguientes expresiones:

$d' = d^{n}$ y $c' = c^{n}$

$d' = \left(\frac{a}{b}\right)^{n}$ y $c' = \left[-\left(\frac{a}{b} \right)\right]^{n}$

$d' = \left(\frac{a}{b} \right)^{n}$ y $c' = \left[(-1)\cdot \left(\frac{a}{b} \right)\right]^{n}$

$d' = \left(\frac{a}{b} \right)^{n}$ y $c' = (-1)^{n}\cdot \left(\frac{a}{b} \right)^{n}$

Si $n$ es impar, entonces:

$d' = \left(\frac{a}{b} \right)^{n}$ y $c' = - \left(\frac{a}{b} \right)^{n}$

(e) El exponente es un positivo par.

Considérese las siguientes expresiones:

$d' = \left(\frac{a}{b} \right)^{n}$ y $c' = \left(\frac{a}{b} \right)^{n}$

Si $n$ es par, entonces $d' = c'$ y la proposición es verdadera.

Por tanto, se concluye que es falso que toda potencia que se obtiene de elevar a un mismo exponente un número racional y su opuesto es la misma.

3 0

3 years ago

Help me pls its Pythagorean theorem I need help

ankoles [38]

Answer:

the answer is 3.81

but rounding it it will be 3.8 meters

Step-by-step explanation:

Pythagorean theorem says

a²+b²=c²

so,

take take the Lowest measurement as a² which will be 7 and take 8 as the hypotenuse or the longest side which is c²

then put it all together you get

7²+x²=8²

we made b as x because we will be finding b

then substitute the values

x²=8²-7²

x²=64-49

x²=15

to remove that square from the x you then put square root in both

✓x²=✓15

press in the calculator, root of 15 will be about 3.81

now we got

x=3.81

x is the missing measurement

8 0

3 years ago

Triangles PQR and STU are similar. The length of PQ = 36 cm, RP = 48 cm and QR = 24

gladu [14]

Answer:

207 cm

Step-by-step explanation:

Because ΔPQR ≅ΔSTU and the longest side in the ΔPQR is RP then the longest side in ΔSTU must be SU = 92 cm

Perimeter of triangle PQR is

P(ΔPQR) = 36+48+24 = 108 cm

Because the triangles are are similar their sides are in proportion.

But how much bigger did the second triangle get?...is (92/48) times bigger

P(ΔSTU) = 180*(92/48) = 207 cm

...you can also use proportions to find each side and then find the perimeter

TU = 24*92 /48 = 46

TS = 36*92/48 = 69

SU = 92

P(ΔSTU) = 92+69+46 =207 cm

*the triangles are not drawn to scale

5 0

2 years ago