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Afina-wow [57]
4 years ago
11

What is your current debt ratio as a percentage to the nearest hundredth?

Mathematics
1 answer:
olasank [31]4 years ago
4 0

Answer:

Step-by-step explanation: see attachment below

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Today is the 65th day of school. If we are out of 180 days, how do I write this as a
jeka57 [31]
13/36 would be the answer I believe
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3 years ago
môt lâm trường lập kế hoạch trồng 1 số ha rừng, theo đó mỗi tuần lâm trường phải trồng 15ha. Trên thực tế nhờ cải tiến kĩ tuật,
Lina20 [59]

Step-by-step explanation:

mình nghĩ là như vầy. Chúc bạn học tôt :))))

8 0
3 years ago
A 500-page book contains 250 sheets of paper. The thickness of the paper used to manufacture the book has mean 0.08 mm and stand
LenaWriter [7]

Answer:

10.20% probability that a randomly chosen book is more than 20.2 mm thick

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

250 sheets, each sheet has mean 0.08 mm and standard deviation 0.01 mm.

So for the book.

\mu = 250*0.08 = 20, \sigma = \sqrt{250}*0.01 = 0.158

What is the probability that a randomly chosen book is more than 20.2 mm thick (not including the covers)

This is 1 subtracted by the pvalue of Z when X = 20.2. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{20.2 - 20}{0.158}

Z = 1.27

Z = 1.27 has a pvalue of 0.8980

1 - 0.8980 = 0.1020

10.20% probability that a randomly chosen book is more than 20.2 mm thick

7 0
4 years ago
Kyle has a storage box that is 2 ft. Long, 3 ft. High, and has a volume of 12 ft. 3 12 ft.3. Myla has a storage box that is 4 ft
Alex17521 [72]

Answer: The widths of Kyle and Myla's boxes is the same as 2 ft.

Step-by-step explanation:

Formula : Volume of cuboidal box = length x width x height

width=\dfrac{Volume}{length\times height}

Given: Kyle has a storage box that is 2 ft. Long, 3 ft. High, and has a volume of 12 ft³ .

width=\dfrac{12}{2\times3}=2\ ft.

Myla has a storage box that is 4 ft. High, 2 ft. Long, and has a volume of 16 ft³.

width=\dfrac{16}{4\times2}=2\ ft.

Hence, the widths of Kyle and Myla's boxes is the same as 2 ft.

4 0
3 years ago
Given the two sets, which statement is true?
monitta
I think it is 3 A but it is hard to know what the question is asking... but my logic is that 3 A is right because A = 1+2 = 3
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4 years ago
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