Answer:Pois(ln(200))
Step-byy-step explanation:
Let N be the number of received calls in a day
That is
N∼Pois(λ).
0.5% = 0.5/100 = 1/200 of no calls
P(N=0)=e^−λ=1/200
-λ=e^(1/200)
λ=in(200)
Our number of calls in a day is distributed Pois(ln(200)).
Answer:
Cost Price = Rs 10000
Step-by-step explanation:
Assume:
Cost of the item = x
Item was sold at a loss of 20%:
Loss = 20% of x = 0.2x
Item sold = x - 0.2x = 0.8x
Item sold at a profit of 10%:
Profit = 10% of x = 0.1x
item sold = x + 0.1x = 1.1x
Solve:
Difference = 1.1x - 0.8x = 0.3x
0.3x = Rs 3000
x = Rs 3000 ÷ 0.3
x = Rs 10000
Answer:
m∠R = 60° and AB ≅ MQ
m∠Q = 56° and CB ≅ RQ
Step-by-step explanation:
Given data :
Prove ΔABC ≅ ΔMQR using SAS
The missing information to prove ΔABC ≅ ΔMQR using SAS
