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Rama09 [41]
3 years ago
6

A function f(x) is said to have a removable discontinuity at x=a if: 1. f is either not defined or not continuous at x=a . 2. f(

a) could either be defined or redefined so that the new function IS continuous at x=a. Let f(x) = {((6)/(x)+(-5 x+18)/(x(x-3)), "if", x doesnt = 0 "and" x doesnt =3),( 3, "if", x=0) :} Show that f(x) has a removable discontinuity at x=0 and determine what value for f(0) would make f(x) continuous at x=0 . Must redefine f(0)= ?
Mathematics
1 answer:
Alexeev081 [22]3 years ago
8 0

Answer:

it would be 5

Step-by-step explanation:

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50 pounds to 35 pounds percentage of change
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Answer:

30%

Step-by-step explanation:

<h2><u>Percentage change </u></h2><h3>formula :</h3>

\frac{change}{origional} * 100

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What is the solution to to the equation x − 2/5 = −1?
ZanzabumX [31]

Answer:

  • x = -0.6

Step-by-step Solution:

<u>Isolate the variable x to get the answer.</u>

  • x − 2/5 = −1
  • => x = -1 + 2/5
  • => x = -1 + 0.4
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Hence, the value of x is -0.6.

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Answer:

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P-24=15

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find the value of a and b for which the system of equations has infinitely many solutions : 2x + 3y = 7 ; (a-b)x + (a+b)y = 3a +
hodyreva [135]

Answer:

a= 5    and   b=1

Step-by-step explanation:

To solve, we will follow the steps below:

2x + 3y = 7

(a-b)x + (a+b)y = 3a + b - 2​

We should note that since it has infinitely many solutions then,

\frac{a_{1} }{a_{2} }   =  \frac{b_{1} }{b_{2} }  = \frac{c_{1} }{c_{2} }

Hence

2/a-b  =  3/a+b   =     7/3a +b-2

2/a-b  =  3/a+b

cross-multiply

3(a-b) = 2( a+b)

open the bracket

3a - 3b = 2a + 2b

collect like term

3a - 2a = 2b + 3b

a = 5b  -------------------------------------------(1)

Similarly

3/a+b   =     7/3a +b-2

cross-multiply

7(a+b)  = 3(3a+b -2)

7a + 7b = 9a + 3b -6

take all the variables to the left-hand side of the equation

7a - 9a+ 7b-3b =   -6

-2a + 4b = -6 ---------------------------------(2)

but a = 5b

substitute a= 5b in equation (2)   and solve for b

-2(5) + 4b = -6

-10  +  4b  = -6

add 10 to both-side of the equation

-10  + 10+ 4b  = -6+10

4b = 4

divide both-side of the equation by 4

b = 1

substitute b= 1 in equation (1)

a = 5b

a =5(1)

a=5

Therefore,   a= 5    and   b=1

8 0
3 years ago
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