Item 14 You develop an app to help students complete their homework. To earn money, you sell advertising space on the app’s main
2 answers:
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Answer:
2. "two thirds of the fourth power of <em>r</em>"
4. n + 14
6. 7 +11n
8. (2/5)n^2
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7. 28
8. 1/5
Step-by-step explanation:
2. "two thirds of the fourth power of <em>r</em>"
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4. "sum" means the listed items are added. You can use any convenient variable to represent "a number." I often use <em>n</em> for <em>n</em><em>umber</em>.
n + 14
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6. "7 more than" means 7 is added to whatever follows. "11 times a number" means the number is multiplied by 11.
7 + 11n
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8. "of" means "times". The square of a number is that number to the power of 2.
(2/5)n^2
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7 & 8 (evaluation). Your calculator can do this. (If not, get one that can.) Note that parentheses are needed around numerators and denominators and anything else that must be treated as a single value.
Answer:
a) i) The drawing of Zeno's route is attached
ii) The bearing of Zeno's return journey is 241° from point C to point A
b) Yes, Zeno returns to Port A before 5.15pm
Step-by-step explanation:
a) i) Please find attached the drawing of Zeno's route
ii) From the attached diagram of Zeno's route created with Microsoft Whiteboard, we find the bearing of his return journey as 241° from point C to point A
b) The distance from point C to point A = 10·√5 km
The speed with which Zeno sails as he returns = 10 km/h
The time it takes Zeno to return t = Distance/Speed
∴ The time it takes Zeno to return t = 10·√5 km/(10 km/h) = √5 h ≈ 2.2361 hours ≈ 2 hours 14 minutes and 9.845 seconds
The time Zeno arrives at point A from point A ≈ 3.00 pm + 2 hours 14 minutes and 9.845 seconds = 5:14.1641 p.m. ≈ 5:14 pm.
Therefore, Zeno returns to Port A before 5.15pm.
