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1 year ago

Hi, can you help me answer this question please, thank you!

Mathematics

1 answer:

matrenka [14]1 year ago

8 0

It is given that the sample size is 17.

So degrees of freedom is 16.

The confidence level is 80%.

Use the t table or a tool to find the critical t value as below:

The one tail t value for 80 percent confidence is 0.865 using t table.

So the critical value is 0.865.

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Simplify: 3x3 (4x4 + 3y)

luda_lava [24]

Answer:

144+27y

Step-by-step explanation:

3x3(4x4+3y)

9(16+3y)

144+27y

5 0

3 years ago

Tim throws darts at a dartboard that has numbers one through 20 in a bull’s-eye in the middle. 10 throws a dart 50 times, and he

Lesechka [4]

Answer:

D.) 1/5

Explanation:

Experimental probability is the ratio of the number of successes to the number of trials.

In this case, success is a bulls-eye. Tim had 10 bulls-eyes. The total number of trials is 50. This makes the experimental probability 10/50, or 1/5.

6 0

3 years ago

Read 2 more answers

What is an equation of the line that passes through the point (6,1) and is

Phoenix [80]

Answer:

just use symbola

and place the two things you have

Step-by-step explanation:

i use it alot it helps you understand the y-intercept and x-intercept and ou can zoom in and zoom out also you can mark the ponts and change the line to make it a different color

5 0

2 years ago

I need help with this graph.

tatuchka [14]

Two parallel lines never intersect, therefore they will never have a solution.

One line could be x=6 and the other could be x=2

Hope this helps :)

3 0

3 years ago

MATH HELP!!! 100PTS!!!

Lostsunrise [7]

Answer:

$x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}$

Step-by-step explanation:

Given functions:

$p(x)=2x-4$

$r(x)=\dfrac{6x-1}{9x+1}$

Solve for p(x) = r(x):

$\begin{aligned}p(x) & = r(x)\\\implies 2x-4 & = \dfrac{6x-1}{9x+1}\\(2x-4)(9x+1)&=6x-1\\18x^2+2x-36x-4&=6x-1\\18x^2-40x-3&=0\end{aligned}$

As the found quadratic equation cannot be factored, use the Quadratic Formula to solve for x:

Quadratic Formula

$x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0$

Therefore:

$a=18, \quad b=-40, \quad c=-3$

Substitute the values of a, b and c into the quadratic formula and solve for x:

$\begin{aligned}\implies x & =\dfrac{-(-40) \pm \sqrt{(-40)^2-4(18)(-3)} }{2(18)}\\\\& =\dfrac{40 \pm \sqrt{1816}}{36}\\\\& =\dfrac{40 \pm \sqrt{4 \cdot 454}}{36}\\\\& =\dfrac{40 \pm \sqrt{4}\sqrt{454}}{36}\\\\& =\dfrac{40 \pm2\sqrt{454}}{36}\\\\& =\dfrac{20 \pm\sqrt{454}}{18}\end{aligned}$

Therefore, the solutions are:

$x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}$

Learn more about quadratic equations here:

brainly.com/question/27750885

brainly.com/question/27739892

6 0

1 year ago