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drek231 [11]
3 years ago
15

Solve the equation x^13-2x^12-x^11+2x^10=0 in the real number system

Mathematics
1 answer:
ASHA 777 [7]3 years ago
3 0

Answer:

x ={0; - 1 ;  2 ;  1}

Step-by-step explanation:

x¹³-2x¹²-x¹¹+2x¹⁰=0

x¹⁰(x³-2x²-x+2)=0

x¹⁰(x+1)(x-2)(x-1)=0

x¹⁰=0    ∨   x+1=0    ∨    x-2=0   ∨   x-1=0

x=0             x= - 1             x= 2          x= 1

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\frac{x}{32}*1600= 400\\50x=400\\x=\frac{400}{50}\\x=8

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