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ehidna [41]
3 years ago
6

Claire jogs 6 miles per hour and Megan jogs 5 miles per hour. they start together at their campsite and jog to an outpost 18 mil

es away. When Claire gets there she immediately turns around and heads back towards Megan. how many miles will they be from the outpost when they meet?
Mathematics
1 answer:
horrorfan [7]3 years ago
6 0

Answer:

16.364 miles

Step-by-step explanation:

Speed of Claire = 6 miles per hour

Speed of Megan= 5 miles per hour

Distance from camp site to out post = 18 miles

Time for Claire to travel=18/6= 3 hours

Time for Megan to travel = 18/5 = 3.6 hours

The time they meet will be equal

Claire distance= 18 + x

Megan distance = 18-x

Claire time =( 18+x)/6

Megan Tim =( 18-x)/5

(18+x)/6 =(18-x)/5

5(18+x)= 6(18-x)

90 +5x = 108-6x

11x=18

X=18/11

X=1.636 Miles

So the distance from the Outpost to where they meet = 18-1.636

= 16.364 miles

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In △ABC, point D∈AC
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<h3>Answer:</h3>
  • ABDC = 6 in²
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<h3>Explanation:</h3>

A diagram can be helpful.

When triangles have the same altitude, their areas are proportional to their base lengths.

The altitude from D to line BC is the same for triangles BDC and EDC. The base lengths of these triangles have the ratio ...

... BC : EC = (1+5) : 5 = 6 : 5

so ABDC will be 6/5 times AEDC.

... ABDC = (6/5)×(5 in²)

... ABDC = 6 in²

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The altitude from B to line AC is the same for triangles BDC and BDA, so their areas are proportional to their base lengths. That is ...

... AABD : ABDC = AD : DC = 4 : 3

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... AABD = 8 in²

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