![\huge \boxed{\mathbb{QUESTION} \downarrow}](https://tex.z-dn.net/?f=%20%5Chuge%20%5Cboxed%7B%5Cmathbb%7BQUESTION%7D%20%5Cdownarrow%7D)
- One angle of a right triangle measures 63°. What is the measure of the other acute angle?
![\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}](https://tex.z-dn.net/?f=%20%5Clarge%20%5Cboxed%7B%5Cmathfrak%7BAnswer%20%5C%3A%20with%20%5C%3A%20Explanation%7D%20%5Cdownarrow%7D)
Given that the triangle is a right angled triangle so one of its angles will be 90°. Then,
- angle 1 = 90°
- angle 2 = 63°
- angle 3 = x
__________________
Find x.
__________________
With the angle sum property of a triangle, we can say that ⇨ <em>angle 1 + angle 2 + angle 3 = 180°</em> (the sum of measurements of all sides in a triangle will be equal to 180°).
__________________
<u>Solving...</u>
angle 1 + angle 2 + angle 3 = 180°
90° + 63° + x = 180°
153° + x = 180°
x = 180° - 153°
x = <u>2</u><u>7</u><u>°</u><u>.</u>
- <u>27°</u> is an acute angle ( 27° is greater than 0° but less than 90°)
__________________
The measure of the other acute angle is <em><u>2</u></em><em><u>7</u></em><em><u>°</u></em><em><u>.</u></em>
-6 is the answer hope this helps
Answer:
w^40
Step-by-step explanation:
When you're dividing exponents with the same base you subtract them
This means that w^15/w^5 = w^10
So we have (w^10)^4
When raising an exponent to another exponenent we multiply them
obviously 10*4 = 40 which gives us our answer: w^40
if you have any questions lmk
Answer: x=1.2
Why?:
This is a 90-60-30 triangle
The sides of 90-60-30 triangle are: 2, square root of 3, 1
2.4/2 = x/1
2.4/2=2x/2
1.2=x
Hope this’ll help
So this would be a multistep equation firs u would want to get ur whole numbers on one side and the ones with the variables on the other so u would have 5p=6p-7 then u would subtract 6p on both sides of the equation so u would have -1p=-7 then u would divide -1p to both sides then u would have p=7