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stellarik [79]
3 years ago
13

calculate the mass of sodium hydroxide you would need to neutralize a solution containing 7.3g of hydrochloric acid

Chemistry
1 answer:
Mashcka [7]3 years ago
4 0
Molar mass of NaOH = 23 + 16 + 1 = 40.0 g/mol

Molar mass of HCl = 1 + 35.5 = 36.5 g/mol

NaOH + HCl = NaCl + H2O

1*40 g NaOH ------> 1*36.5 g HCl
        g NaOH -------> 7.3 g HCl

36.5 g  = 40 * 7.3

36.5 g = 292

mass ( NaOH ) = 292 / 36.5

mass ( NaOH ) = 8.0 g of NaOH

hope this helps!.

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A cylinder of argon gas contains 50.0 L or Ar at 18.4 atm and 'C. How many moles of argon are in the cylinder?
makkiz [27]

<em>A cylinder of argon gas contains 50.0 L of  Ar  at 18.4 atm and 127 °C. How many moles of argon are in the cylinder?</em>

<em />

Number moles of Argon : 28.03

<h3>Further explanation</h3>

Given

The volume of gas=50 L

P = 18.4 atm

T = 127+273=400 K

Required

moles of Argon

Solution

Use ideal gas Law :

\tt n=\dfrac{PV}{RT}\\\\n=\dfrac{18.4\times 50}{0.08205\times 400}\\\\n=28.03

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Consider a car being acted on by balanced forces. Can you conclude whether the car is moving or at rest? Explain your response.
olga55 [171]
First, an object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force.

But what exactly is meant by the phrase unbalanced force? One force - the Earth's gravitational pull - exerts a downward force. The other force - the push of the table on an object.

Since these two forces are of equal magnitude and in opposite directions, they balance each other. An object is said to be at equilibrium. There is no unbalanced force acting upon the object and thus the object maintains its state of motion. When all the forces acting upon an object balance each other, the object will be at equilibrium; it will not accelerate.
Consider another example involving balanced forces - a person standing on the floor. There are two forces acting upon the person. The force of gravity exerts a downward force. The floor exerts an upward force.

Since these two forces are of equal magnitude and in opposite directions, they balance each other. The person is at equilibrium. There is no unbalanced force acting upon the person and thus the person maintains its state of motion.

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Now consider a book sliding from left to right across a tabletop. Sometime in the prior history of the book, it may have been given a shove and set in motion from a rest position. Or perhaps it acquired its motion by sliding down an incline from an elevated position. Whatever the case, our focus is not upon the history of the book but rather upon the current situation of a book sliding to the right across a tabletop. The book is in motion and at the moment there is no one pushing it to the right.

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In conclusion

To determine if the forces acting upon an object are balanced or unbalanced, an analysis must first be conducted to determine what forces are acting upon the object and in what direction. If two individual forces are of equal magnitude and opposite direction, then the forces are said to be balanced. An object is said to be acted upon by an unbalanced force only when there is an individual force that is not being balanced by a force of equal magnitude and in the opposite direction.

Hope all this help you to understand the topic of balance and unbalance forces
3 0
3 years ago
A reaction vessel contains 10.0 g of CO and 10.0 g of O2. How many grams of CO2 could be produced according to the following rea
iren2701 [21]

Answer:

1. 15.71 g CO2

2. 38.19 % of efficiency

Explanation:

According to the balanced reaction (2 CO(g) + O2(g) → 2 CO2(g)), it is clear that the CO is the limitant reagent, because for every 2 moles of CO we are using only 1 mole of O2, so even if we have the same quantity for both reagents, not all of the O2 will be consumed. This means that we can just use the stoichiometric ratios of the CO and the CO2 to solve this question, and for that we need to convert the gram units into moles:

For CO:

C = 12.01 g/mol

O = 16 g/mol

CO = 28.01 g/mol

(10.0g CO) x (1 mol CO/28.01 g) = 0.3570 mol CO

For CO2:

C = 12.01 g/mol

O = 16 x 2 = 32 g/mol

CO2 = 44.01 g/mol

We now that for every 2 moles of CO we are going to get 2 moles of CO2, so we resolve as follows:

(0.3570 mol CO) x (2 mol CO2/2 mol CO) = 0.3570 moles CO2

We are obtaining 0.3570 moles of CO2 with the 10g of CO, now lets convert the CO2 moles into grams:

(0.3570 moles CO2) x (44.01 g/1 mol CO2) = 15.71 g CO2

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From the previous result, we know that if we produce 15.71 CO2 with all the 10g of CO used, we would have an efficiency of 100%. So to know what would that efficiency be if we would only produce 6g of CO2, we resolve as follows,

(6g / 15.71g) x 100 = 38.19 % of efficiency

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Answer:

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