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Amiraneli [1.4K]
3 years ago
14

Pl hep help help me

Chemistry
1 answer:
ivanzaharov [21]3 years ago
4 0
It is true

I’ve done this before
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Atoms of the same chemical element that have different atomic mass are known as?
monitta

Answer:

isotopes

Explanation:

The atoms of a chemical element can exist in different types. These are called isotopes. They have the same number of protons (and electrons), but different numbers of neutrons. Different isotopes of the same element have different masses.

8 0
3 years ago
What is the mass of one mole of hydrogen molecules?
Lilit [14]

Answer:

2 grams

Explanation:

One MOLE of hydrogen atoms contains the same number of atoms as the number of hydrogen molecules in one MOLE of hydrogen molecules, i.e., Avagadros number. However, one mole of hydrogen atoms has a mass of 1 gram while one MOLE of hydrogen molecules has a mass of 2 grams.

4 0
3 years ago
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Which of the following is NOT studied in Earth Science?
xxTIMURxx [149]

Answer:

the answer to your question is B

3 0
3 years ago
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which equation is setup correctly to determine the volume of a 1.5 mol sample of oxygen gas at 22 degrees Celsius and 100 kPa
rjkz [21]
Hello!

We have the following data:


v (volume) = ? (in L)
n (number of mols) = 1,5 mol
T (temperature) = 22 ºC 
First let's convert the temperature on the Kelvin scale, let's see:
TK = TºC + 273,15
TK = 22 + 273,15
TK = 295,15

P (pressure) = 100 kPa → P = 100000 Pa → P ≈ 0,987 atm
R (gas constant) = 0,082 atm.L / mol.K

<span>We apply the data above to the Clapeyron equation (gas equation), let's see:

</span>P*V = n*R*T

0,987*V = 1,5*0,082*295,15

0,987V = 36,30345

V =  \dfrac{36,30345}{0,987}

\boxed{\boxed{V \approx 36,78\:L}} \end{array}}\qquad\checkmark

I hope this helps. =)
4 0
4 years ago
4.) A In an experiment, 1.056 g of a metal carbonate,
yKpoI14uk [10]
<h3>Answer:</h3>

M= Cu

<h3>Explanation:</h3>

From the question;

Mass of metal carbonate = 1.056 g

Mass of CO₂ = 0.376 g

We are required to identify the metal M in the carbonate

The equation for the combustion of the carbonate;

MCO₃(s) + heat → MO(s) + CO₂(g)

<h3>Step 1: Calculating the number of moles of CO₂</h3>

Moles = Mass ÷ molar mass

Molar mass CO₂ = 44.01 g/mol

Moles = 0.376 g ÷ 44.01 g/mol

          = 0.00854 Moles

<h3>Step 2: Determining the moles of MCO₃ </h3>

From the equation;

1 mole of the metal carbonate decomposes to yield 1 mole CO₂

Therefore; Mole ratio of MCO₃ : CO₂ = 1 : 1

Hence; Moles of MCO₃ = 0.00854 moles

<h3>Step 3: Determining the molar mass of MCO₃</h3>

Moles of MCO₃ = 0.00854 moles

Mass of the carbonate = 1.056 g

But;

Molar mass = Mass ÷ moles

                   = 1.056 g ÷ 0.00854 moles

                   = 123.65 g/mol

<h3>Step 4: Atomic mass of the metal </h3>

The molar mass of metal carbonate = 123.65 g/mol

Atomic mass of carbon = 16

Atomic mass of oxygen = 12.01

Therefore;

123.65 g = M + 12.01 + (16 ×3)

M = 63.64 g

The atomic mass of M is 63.64 approximately the same as that of copper.

Atomic mass of Cu is 63.546

Therefore, identity of M is Cu

3 0
3 years ago
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