Use the specific heat equation to solve this.
Answer: The answer would be 6247.142 g
Explanation:
Hey there!
Molar mass of O3 = 47.9982 g/mol
therefore:
1 mole O₃ --------------------- 47.9982 g
moles O₃ ---------------------- 24 g
moles O₃ = 24 x 1 / 47.9982
moles O₃ = 24 / 47.9982
moles O₃ = 0.500 moles
Hope this helps!
The given statement is true .
<h3>What is Rutherford’s gold foil experiment?</h3>
- A piece of gold foil was hit with alpha particles, which have a favorable charge. Most alpha particles went right around. This showed that the gold particles were mostly space.
- The Rutherford gold leaf investigation supposed that most (99%) of all the mass of an atom is in the middle of the atom, that the nucleus is very small (105 times small than the length of the atom) and that is positively captured.
- For the distribution experiment, Rutherford enjoyed a metal sheet that could be as thin as practicable. Gold is the most malleable of all known metals. It can easily be converted into very thin sheets. Hence, Rutherford established a gold foil for his alpha-ray scattering experimentation.
To learn more about Rutherford’s gold foil experiment, refer to:
brainly.com/question/4113533
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