3 years ago

How to solve the problem

Mathematics

1 answer:

777dan777 [17]3 years ago

4 0

Hope this helps.....

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What does the remainder theorem conclude given that f(x)x+3 has a remainder of 11?

Slav-nsk [51]

By the remainder theorem of polynomial division, the complete equation is f(-3) = 11

<h3>How to complete the blanks?</h3>

The equation is given as:

f(x)/x + 3

Set the divisor to 0

x + 3 = 0

Solve for x

x = -3

Given that the quotient has a remainder of 11.

It means that:

f(-3) = 11

Hence, the complete equation is f(-3) = 11

Read more about remainder theorem at:

brainly.com/question/13328536

#SPJ1

5 0

2 years ago

Can someone help me find x.

Harman [31]

Answer:

Step-by-step explanation:

6x+9=63

6x=63-9

6x=54

x=54/6

x=9

I encourage you to figure out the justification yourself.

8 0

3 years ago

Plz tell me the correct answer

musickatia [10]

Answer: H

Step-by-step explanation:

6 0

2 years ago

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Rectangle ABCD has m∠ACD=5x−4 and m∠BAC=4x+5. <br> Find m∠CAD. m∠CAD=

EleoNora [17]

Answer:

did you ever get the answer?

Step-by-step explanation:

3 0

2 years ago

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(x-1)(x-3)(x+5)(x+7)=297

mihalych1998 [28]

First simplify the expression into polynomial form,

$(x-1)(x-3)(x+5)(x+7)=297$

$x^4+8x^3-10x^2-104x+105=297$

$x^4+8x^3-10x^2-104x-192=0$

Now factor into,

$(x-4)(x+8)(x^2+4x+6)=0$

Which means the solutions are,

$x-4=0\implies\boxed{x_1=4}$

$x+8=0\implies\boxed{x_2=-8}$

and then two complex solutions because determinant of the third factor $D\lt0$ ,

$x^2+4x+6=0$

$x^2+4x+4=-2$

$(x+2)^2=-2\implies\boxed{x_3=i\sqrt{2}-2},\boxed{x_4=-i\sqrt{2}-2}$

Hope this helps :)

5 0

3 years ago

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