Answer:
Step-by-step explanation:
Answer:
The answer is 4
Step-by-step explanation:
g(x)=3x-2
g(2)=3*2-2=6-2=4
Answer:
H0: μ = 5 versus Ha: μ < 5.
Step-by-step explanation:
Given:
μ = true average radioactivity level(picocuries per liter)
5 pCi/L = dividing line between safe and unsafe water
The recommended test here is to test the null hypothesis, H0: μ = 5 against the alternative hypothesis Ha: μ < 5.
A type I error, is an error where the null hypothesis, H0 is rejected when it is true.
We know type I error can be controlled, so safer option which is to test H0: μ = 5 vs Ha: μ < 5 is recommended.
Here, a type I error involves declaring the water is safe when it is not safe. A test which ensures that this error is highly unlikely is desirable because this is a very serious error. We prefer that the most serious error be a type I error because it can be explicitly controlled.
Answer:
(-2, -4)
Step-by-step explanation:
–2x + 2y = -4
3х + Зу = -18
Divide the first equation by 2
–2x/2 + 2y/2 = -4/2
-x +y = -2
Divide the second equation by 3
3х/3 + Зу/3 = -18/3
x + y = -6
Add these equation together
-x +y = -2
x + y = -6
-------------------
0x + 2y = -8
2y = -8
Divide each side by 2
2y/2 = -8/2
y = -4
Now we need x
x+y = -6
x-4 = -6
Add 4 to each side
x-4+4 = -6+4
x = -2
Answer:
8.5$
Step-by-step explanation:
85 diveded by 10 is 8.5$.
