All categories

2 years ago

Given sin b = .88 find angle b in radians

Mathematics

1 answer:

vazorg [7]2 years ago

5 0

first convert 0.88 to degrees

so arcsin(0.88) = 61.642 degrees

Arcsin on a calculator is sin^-1

then to convert to radians divide degrees by 180 and multiply that by PI

so (61.642/180) x PI = 1.076 radians

You might be interested in

Hi can some please help?

Oduvanchick [21]

So I'm assuming that you're taking Calculus.
The first thing you want to do is take the integral of f(x)...
Use the power rule to get:
4X^2-13X+3.
Now solve for X when f(x)=0. This is because when the slope is 0, it is either a minimum or a maximum(I'm assuming you know this)
Now you get X=0.25 and X=3. Since we are working in the interval of (1,4), we can ignore 0.25
Thus our potential X values for max and min are X=1,X=4,X=3(You don't want to forget the ends of the bounds!)
Plugging these value in for f(x), we get
f(1)=2.833
f(3)=-8.5
f(4)=1.667
Thus X=1 is the max and X=3 is the min.
So max:(1,2.833)
min:(3,-8.5)

Hope this helps!

3 0

2 years ago

Factor the expression using GCF of 4+22

xxMikexx [17]

Answer:

the answer would be 2(2+11)

Step-by-step explanation:

6 0

2 years ago

Please help me solve my problem!!!

Nookie1986 [14]

Answer:

B. sometimes

Step-by-step explanation:

Consecutive angles of a parallelogram are same side interior angles of two parallel lines cut by a transversal, so they are always supplementary.

Supplementary angles are two angles whose measures add to 180 deg.

If two angles are supplementary and one angle measures 90, then the other angle also measures 90 deg, and the two angles are congruent. If one angle measures less than 90 deg, then the other measure more than 90 deg and are not congruent. Therefore, these angles may or may not be congruent.

Answer: sometimes

7 0

2 years ago

Sin(60-theta)sin(60+theta)

ehidna [41]

Step-by-step explanation:

$\sin(60 - \theta) \sin(60 + \theta) \\ = \{ \sin(60) \cos( \theta) - \sin( \theta) \cos(60) \} \{ \sin(60) \cos( \theta) + \cos(60) \sin( \theta) \} \\ = \{ \frac{ \sqrt{3} }{2} \cos( \theta) - \frac{1}{2} \sin( \theta) \} \{ \frac{ \sqrt{3} }{2} \cos( \theta) + \frac{1}{2} \sin( \theta) \} \\ \\$

from difference of two squares:

${ \boxed{(a - b)(a + b) = ( {a}^{2} - {b}^{2} ) }}$

therefore:

$= \{ {( \frac{ \sqrt{3} }{2}) }^{2} { \cos }^{2} \theta \} - \{ {( \frac{ \sqrt{3} }{2} )}^{2} { \sin }^{2} \theta \} \\ \\ = \frac{3}{4} { \cos }^{2} \theta - \frac{3}{4} { \sin}^{2} \theta$

factorise out ¾ :

$= \frac{3}{4} ( { \cos }^{2} \theta - { \sin}^{2} \theta) \\ \\ = { \boxed{ \frac{3}{4} \cos(2 \theta) }}$

3 0

2 years ago

Read 2 more answers

Mrs. Stevenson wants to split her class into 4 teams: Team A, Team B, Team C, and Team D. There are 28 students in her class. To

olga_2 [115]

The probability that both of the students are on Team D is about 5.56%

There are 4 teams, so the first person has a 1/4 chance of being on Team D.

However, for the second person, there are only 6 spots left out of 27 to be on Team D.

To find the combined probability, we need to multiply the two fractions.

1/4 times 6/27 = 1/18 or about 5.56%

3 0

2 years ago