The answer is -2.
im sorry if the work is messy.
Observations can you make from a comparison of the number of water supply stoppages reported by owner-occupied units versus renter-occupied units 1.
Total no. of times owner-occupied units had a water supply stoppage lasting 6 or more hours
547000 + 5012000 + 6110000 + 2544000 + 557000 = 14770000
x = no. of times owner-occupied units had a water supply stoppage.
<h3>What is the probability at x =0?</h3>
P(x=0) = 547000/14770000
P(x=0) = 0.0370
Similarly, we have at x=1
P(x=1) = 5012000/14770000
P(x=1) = 0.3393
P(x=2) = 6110000/14770000
P(x=2) = 0.4137
P(x=3) = 2544000/14770000
P(x=3) = 0.1722
P(x=4) = 557000/14770000
P(x=4) = 0.0378
x f(x)
0 0.0370
1 0.3393
2 0.4137
3 0.1722
4 0.0378
Total 1
Observations can you make from a comparison of the number of water supply stoppages reported by owner-occupied units versus renter-occupied units 1.
To learn more about the probability distribution visit:
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Answer:
b = -17
Step-by-step explanation:
-2b - 12 = 22
+12 +12
-2b = 34
-2b/-2 34/-2
b = -17
Answer:
Step-by-step explanation:
question no . 5
ratio of angle L
take angle as reference angle
using cos rule
cos L = base / hypotenuse
= 4/5
ratio of angle N
take angle N as reference angle
using sin rule
sin N = opposite / hypotenuse
= 4/5
for measure of angle L
cos L = 4/5
cos L = 0.8
L = 
L = 36.9
for meanure of angle N
sin N = 4/5
sin N = 0.8
N = 
N = 53.1
